usman7 wrote:
Q1: A parking garage has places for a c ertain number of cars. If 1/5 of the places are left empty, and 2/5 of the places are used by compact cars, non-compact cars take up what fraction of the filled spaces in the garage.
A) 1/3 B) 2/5 C) 1/2 D) 3/5 E) 4/5
I solved the question as follows:
4/5 of the places are not empty and 4/5-2/5 will give us the fraction non-compact cars i.e. 2/5. However the answer is 1/2. If i plug in, I get the right answer i.e. 1/2 but why cant I solve it using the above method?
Can somebody explain and solve the question with the ratios as done above without plugin in.
Q2 If p and q are integers, such that p<0<q, and s is a non negative integer, which of the following must be true?
A) p^2 < q^2 B) P + q = 0 C) sp < sq D) sp (is not =) sq E) p/q < s
I was getting multiple true statements. Please solve...
For qestion 1)
2/5 are used by non compact cars
the garage is filled up to 4/5 it capacity
So 2/5 / 4/5 = 1/2
For question 2)
Posted: Sun Sep 10, 2006 6:23 am Post subject: Help needed on the following questions
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Q1: A parking garage has places for a c ertain number of cars. If 1/5 of the places are left empty, and 2/5 of the places are used by compact cars, non-compact cars take up what fraction of the filled spaces in the garage.
A) 1/3 B) 2/5 C) 1/2 D) 3/5 E) 4/5
I solved the question as follows:
4/5 of the places are not empty and 4/5-2/5 will give us the fraction non-compact cars i.e. 2/5. However the answer is 1/2. If i plug in, I get the right answer i.e. 1/2 but why cant I solve it using the above method?
Can somebody explain and solve the question with the ratios as done above without plugin in.
Q2 If p and q are integers, such that p<0<q, and s is a non negative integer, which of the following must be true?
A) p^2 < q^2 B) P + q = 0 C) sp < sq D) sp (is not =) sq E) p/q < s
A ---if p=-5 and q=1 A fails
B----Need not necessarily
C----Need not necessarily True since p<q and s being a non negetive int it might be 0
D----Not True since p is -ve and q is +ve but S might be 0
E---since S is always either 0 or + ve int