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Q27: In the figure, points A, B, C, D, and E lie on a line. [#permalink]
08 Oct 2006, 23:52

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

Q27:

In the figure, points A, B, C, D, and E lie on a line. A is on both circles, B is the center of the smaller circle, C is the center of the larger circle, D is on the smaller circle, and E is on the larger circle. What is the area of the region inside the larger circle and outside the smaller circle?
(1) AB = 3 and BC =2
(2) CD =1 and DE = 4

Am getting D

[color=white]Answer is given as A. What do you guyz think.

My logic for B is also sufficient is

CD + DE = AC = AB + BC

=> AB + BC = 5

AD = AB + BC + CD = 5 + 1 = 6 AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3 CE is the radius of the bigger circle = 5

AD = AB + BC + CD = 5 + 1 = 6
AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3
CE is the radius of the bigger circle = 5

B gives you enough information to deduce the diameter of the smaller circle, allowing you to find the area. B clearly gives enough information to find the area of the larger circle.

In the figure, points A, B, C, D, and E lie on a line. A is on both circles, B is the center of the smaller circle, C is the center of the larger circle, D is on the smaller circle, and E is on the larger circle. What is the area of the region inside the larger circle and outside the smaller circle?
(1) AB = 3 and BC =2
(2) CD =1 and DE = 4

1) 25*pi - 9 *pi Sufficient
2) I can't find the radius of smaller circle so no area

AD = AB + BC + CD = 5 + 1 = 6 AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3 CE is the radius of the bigger circle = 5

From this we can calculate.

Please correct!!

The problem with your calculation is that from B we do not know what are the values of AB and BC....

AD = AB + BC + CD = 5 + 1 = 6 AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3 CE is the radius of the bigger circle = 5

From this we can calculate.

Please correct!!

Hey simaQ, what's wrong with this logic? Clearly from 2 statement we get the radius of bigger circle From the above logic we r getting AB which is the radius of smaller circle.

Great to know you are joining Kellogg. A lot was being talked about your last minute interview on Pagalguy (all good though). It was kinda surprise that you got the...