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Q27: In the figure, points A, B, C, D, and E lie on a line. [#permalink]
 09 Oct 2006, 00:52
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Q27:
In the figure, points A, B, C, D, and E lie on a line. A is on both circles, B is the center of the smaller circle, C is the center of the larger circle, D is on the smaller circle, and E is on the larger circle. What is the area of the region inside the larger circle and outside the smaller circle?
(1) AB = 3 and BC =2
(2) CD =1 and DE = 4
Am getting D
[color=white]Answer is given as A. What do you guyz think.
My logic for B is also sufficient is
CD + DE = AC = AB + BC
=> AB + BC = 5
AD = AB + BC + CD = 5 + 1 = 6
AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3
CE is the radius of the bigger circle = 5
From this we can calculate.[/color]
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Director
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I got A....
We need to know the area of both of the circles, therefore we need to know the radius of both of the circles...
B) only provides the radius of the larger circle....
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Director
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Straight A.
using 1, we can get area of both circles (hence desired area), while 2 is insufficent.
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Manager
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My logic for B is also sufficient is
CD + DE = AC = AB + BC
=> AB + BC = 5
AD = AB + BC + CD = 5 + 1 = 6
AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3
CE is the radius of the bigger circle = 5
From this we can calculate.
Please correct!!
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Manager
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I agree with withme.
B gives you enough information to deduce the diameter of the smaller circle, allowing you to find the area. B clearly gives enough information to find the area of the larger circle.
So D it is
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SVP
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(D) as well.
r = Radius of the small circle
R = Radius of the big circle
Stat1:
o AB = 3 = r
o R = AC = AB + BC = 3 + 2 = 5
SUFF
Stat2:
o R = CE = CD + DE = 1 + 4 = 5
o r = (2*R-DE) /2 = (10-4)/2 = 3
SUFF
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Director
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In the figure, points A, B, C, D, and E lie on a line. A is on both circles, B is the center of the smaller circle, C is the center of the larger circle, D is on the smaller circle, and E is on the larger circle. What is the area of the region inside the larger circle and outside the smaller circle?
(1) AB = 3 and BC =2
(2) CD =1 and DE = 4
1) 25*pi - 9 *pi Sufficient
2) I can't find the radius of smaller circle so no area
A is my answer
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SVP
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withme, what is the source of this question? 
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Director
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D
Statement 1:
Radius of smaller circle = AB =3; area = 9pi
Radius of larger circle = AC = 5; area = 25pi SUFF
Statement 2:
Radius of larger circle = CD+DE = 5; area = 25pi
Radius of smaller circle = (DC+CA)/2 = 3; area = 9pi SUFF
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Director
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withme wrote: My logic for B is also sufficient is
CD + DE = AC = AB + BC
=> AB + BC = 5
AD = AB + BC + CD = 5 + 1 = 6
AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3
CE is the radius of the bigger circle = 5
From this we can calculate.
Please correct!!
The problem with your calculation is that from B we do not know what are the values of AB and BC....
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Director
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cicerone wrote: SimaQ wrote: withme wrote: My logic for B is also sufficient is
CD + DE = AC = AB + BC
=> AB + BC = 5
AD = AB + BC + CD = 5 + 1 = 6
AB is the radius of the smaller circle and AD is the diameter of the smaller circle. => AB = AD/2 = 3
CE is the radius of the bigger circle = 5
From this we can calculate.
Please correct!! Hey simaQ, what's wrong with this logic? Clearly from 2 statement we get the radius of bigger circle From the above logic we r getting AB which is the radius of smaller circle. So answer must be D Ok, yes the answer should be D...
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