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Q30: M = {-6, -5, -4, -3, -2} T = {-2, -1, 0, 1, 2, [#permalink]
 26 Aug 2006, 08:50
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Q30:
M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
A. 0
B. 1/3
C. 2/5
D. 1/2
E. 3/5
_________________
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shinewine
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shinewine wrote: Q30:
M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
A. 0
B. 1/3
C. 2/5
D. 1/2
E. 3/5
I go with D
Required probability = P(2 picks are of opposite sign)
We know that the first pick is always negative. Hence it is suffiencent to calculate probability that 2nd pick is positive. Since there are 3 nos. that are positive out of 6 in the set T
This is 3/6 or 1/2
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Current Student
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Probability = #favorable outcomes/#possible outcomes
neg*pos=neg: half of the numbers (3) in set T are pos.
probability = 3/6 ---> 1/2
(D)
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Senior Manager
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Getting D....
Total no. of possible outcomes = 6*6 = 36
Total no. of outcomes with negative product = 6+6+6 (each for 1,2,3 members for set T)
Hence answer = 18/36 = 1/2
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Senior Manager
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D as well
For the outcome to be negative T has to be > 0 and positive
prob(T positive and >0) = = 3/6 = 1/2
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Total possibilities of selecting a number from M and one from T = 30
Possibilities with product is -ve = 15
Hence prob = 15/30 = 1/2
D
Heman
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