Q31: A small, rectangular park has a perimeter of 560 feet : Quant Question Archive [LOCKED]
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# Q31: A small, rectangular park has a perimeter of 560 feet

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Joined: 18 Oct 2004
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Q31: A small, rectangular park has a perimeter of 560 feet [#permalink]

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05 Nov 2004, 20:20
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Q31:
A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 200 feet. What is its area, in square feet?

A. 19,200
B. 19,600
C. 20,000
D. 20,400
E. 20,800

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05 Nov 2004, 20:22
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Best Regards,

Paul

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05 Nov 2004, 21:05
Maitri,
Pls post the OA after say 24 or 36 hrs - by which time we would have had some quality discussion from the members. A immediate OA along with the question does not challenge anyone.

Approach to this problem..

Two equn's
1. l + w = 280 (since 2(l+w) = 560))
=> (l+w)^2 = l^2 + w^2 + 2lw = 280^2

2. l^2 + w^2 = 200^2

combining 1 and 2 we have 2lw = 280^2 - 200^2 = 38400
so, lw = area = 19200.
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05 Nov 2004, 21:15
Hey Venksune, I love your approach. Kudos
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Best Regards,

Paul

05 Nov 2004, 21:15
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