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Q7: What is the value of x + 7 ? (1) x + 3 = 14 (2) (x +

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Senior Manager
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Q7: What is the value of x + 7 ? (1) x + 3 = 14 (2) (x + [#permalink] New post 08 Mar 2007, 21:07
00:00
A
B
C
D
E

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(N/A)

Question Stats:

67% (01:21) correct 33% (01:17) wrong based on 4 sessions
Q7: What is the value of ¦x + 7¦?
(1) ¦x + 3¦= 14
(2) (x + 2)^2 = 169

My answer is B.

(1) |x+3| = 14
Here x is either 11 or -17.

if x = 11
|11+3| = 14

and if x = -17
|-17+3 = -14| = 14

Since we have two values for x, the statement is NOT-SUFFICIENT. (In DS we must have ONE confirmed answer)

(2) (x+2)^2 = 169
(x+2) = 13
x = 11

Statement (2) has only one confirmed answer for x, so B alone is SUFFICIENT.

Am I right?

Another case suppose statement (2) is (x+2)2 = 169 as given by original poster.
(x+2) = 169/2 = 84.5
x = 82.5

|x+7| will be |84.5 + 7| or |91.5| (First time for me to see a fraction/decimal in absolute value).......any help here?
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 [#permalink] New post 08 Mar 2007, 21:22
(2) (x+2)^2 = 169
(x+2) = 13
x = 11

Statement (2) has only one confirmed answer for x, so B alone is SUFFICIENT
(x+2)^2 = 169
|x+2|=13
two options for x hence insuf
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 [#permalink] New post 08 Mar 2007, 21:39
Hi Yurik79 :)

You gave the answer D and then C to the same question here
http://www.gmatclub.com/phpbb/viewtopic.php?t=42256

So I was confused and posted the question separately with my answer.
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 [#permalink] New post 08 Mar 2007, 22:29
Quote:
(2) (x+2)^2 = 169
(x+2) = 13
x = 11


Summer Answer to this is C.

In your calculations above
X+2 can be either +13 or -13.

So B alone is not sufficient.

But if both A and B are given then X has to be 11.

So C is answer
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 [#permalink] New post 08 Mar 2007, 22:31
Summer3 wrote:
Hi Yurik79 :)

You gave the answer D and then C to the same question here
http://www.gmatclub.com/phpbb/viewtopic.php?t=42256

So I was confused and posted the question separately with my answer.

Yes I remember that answer is C for this one
I just tried to explain why 2 st is insuff alone
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 [#permalink] New post 08 Mar 2007, 23:10
Oh yes, I also got it now. You are right! Answer should be C.
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Re: Absolute Value DS [#permalink] New post 11 Mar 2007, 00:26
Summer3 wrote:
Q7: What is the value of ¦x + 7¦?
(1) ¦x + 3¦= 14
(2) (x + 2)^2 = 169

My answer is B.

(1) |x+3| = 14
Here x is either 11 or -17.

if x = 11
|11+3| = 14

and if x = -17
|-17+3 = -14| = 14

Since we have two values for x, the statement is NOT-SUFFICIENT. (In DS we must have ONE confirmed answer)

(2) (x+2)^2 = 169
(x+2) = 13
x = 11

Statement (2) has only one confirmed answer for x, so B alone is SUFFICIENT.

Am I right?

Another case suppose statement (2) is (x+2)2 = 169 as given by original poster.
(x+2) = 169/2 = 84.5
x = 82.5

|x+7| will be |84.5 + 7| or |91.5| (First time for me to see a fraction/decimal in absolute value).......any help here?


My Amswer is E

|x+3| =14 => x could be 11 or -17
(x+2)^2 = 169 => x+2 = 13 or x+2 = -13 => x could be 11 or -17
So, both are insufficient=> So, the correct answer is E
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 [#permalink] New post 11 Mar 2007, 00:31
Answer should be C

Explanation:

from one you have rightly found the value of X to be either 11 or -17 so 1 is insufficient. similarly from 2) we got x could be either 11 or -15 so 2 is also in sufficient.

If we combine both we have X=11 as a common answer, which is sufficient to answer the analogy. so answer is C

regards,

Amardeep
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 [#permalink] New post 11 Mar 2007, 01:28
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Q7: What is the value of ¦x + 7¦?
(1) ¦x + 3¦= 14
(2) (x + 2)^2 = 169

(C) for me too :)

From 1
Case 1 : x+3 < 0
|x + 3|= 14
<=> -(x+3) = 14
<=> x = -17

Case 2 : x+3 > 0
|x + 3|= 14
<=> x+3 = 14
<=> x = 11

Now, let check out the values of |x+7| with these 2 values of x.
o If x = -17, then |x+7| = |-17 + 7| = 10
o If x = 11, then |x+7| = |11 + 7| = 18

INSUFF.

From 2
(x + 2)^2 = 169
<=> (x + 2)^2 - 13^2 = 0
<=> ((x+2) + 13) * ((x+2) - 13) = 0
<=> (x + 15) * (x - 11) = 0
<=> x= -15 or x = 11

Now, let check out the values of |x+7| with these 2 values of x.
o If x = -15, then |x+7| = |-15 + 7| = 8
o If x = 11, then |x+7| = |11 + 7| = 18

INSUFF.

Combined (1) with (2)
The system of solutions for x is:
o x = -17 or x = 11
and
o x= -15 or x = 11

That forces x to be equal to 11. So, |x+7| has 1 and only one value that is 18.

SUFF.
  [#permalink] 11 Mar 2007, 01:28
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