The table above shows the number of students in three clubs at McAulif

There are formulas for this sort of problem.
In this case, I prefer a Venn diagram.

We have totals for each club, and the overlap numbers.
Find the students who are in ONLY one club with the Venn diagram.

Draw the diagram, and write in information.
Start with the most restrictive information: there are 0 in all three clubs
Next most restrictive: the number in the intersections (10, 5, 6)
Finally, derive the number of students who are in ONLY one club from CLUB TOTAL - TWO OVERLAPs, for each club

Add all the numbers inside the Venn diagram.
That is the number of different students in the three clubs.

GIVEN (write this info in the diagram)
Chess total = 40
Drama total = 30
Math total = 25
C + D = 10
C + M = 5
D + M = 6
All three = 0

DERIVE how many in ONLY ONE
Chess ONLY (purple shaded region):
Total must equal 40
(10 + 5 = 15) (gray regions) of those 40 are in other clubs.
Chess only: (40 - 15) = 25

Drama ONLY? (green shaded region)
Total must equal 30.
(10 + 6) = 16 (gray regions) of those 30 are in other clubs.
Drama only: (30 - 16) = 14

Math ONLY? (pink shaded region)
Total must equal 25
(5 + 6) = 11 (gray regions) are in other clubs.
Math only: (25 - 11) = 14

Add the numbers in each region:
25 + 14 + 14 + 10 + 6 + 5 = 74

Answer C