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QR DS 63: A Town T has 20,000 residents, 60 percent of whom [#permalink]
21 Feb 2011, 06:06

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Difficulty:

5% (low)

Question Stats:

63% (02:30) correct
37% (01:08) wrong based on 19 sessions

QR DS 63: A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T. (2) The number of female residents who were not born n Town T is twice the number of female residents who were born in Town T.

A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

This question can be best described using a table. I don't know how would I draw that. Someone please suggest.

Female=12000 Male=8000

Female born in T=x Female not born in T=12000-x

Male born in T=y Male not born in T= 8000-y

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T. x=2*y Not sufficient.

(2) The number of female residents who were not born n Town T is twice the number of female residents who were born in Town T. 12000-x=2x 3x = 12000 x=4000 We know the number of female born in T; 4000; Number of females not born; 8000 Know nothing about the male born in T i.e. y.

Combining both; x=2y 4000 = 2y y=2000

Total people born in T=2000+4000=6000 or (6/20)*100=30% Sufficient.

Re: A complicated Math, which has not been discussed. [#permalink]
16 Aug 2011, 07:00

the question seems to be incorrect.. in the final equation, i get total male as 6000 whereas the question gives 8000.. experts, any comments?? _________________

Appreciation in KUDOS please! Knewton Free Test 10/03 - 710 (49/37) Princeton Free Test 10/08 - 610 (44/31) Kaplan Test 1- 10/10 - 630 Veritas Prep- 10/11 - 630 (42/37) MGMAT 1 - 10/12 - 680 (45/34)

let's make a table and write all values from stem, statement 1 & 2

From Stem, total females = 60% of 20,000 = 12,000 From statement 1, if male(M) not born (NB) in town T are x, then female(F) born(B) in town = 2x From statement 2, F(NB) = 2 F(B) Combining both the statements, we have following table

| M | F | -------|-------|------- |--------- B | | 2x | -------|-------|------- |-------- NB | x | 2(2x) | -------|-------|--------|------------ | | 12000 |

So, 2x + 2(2x) = 12,000.

Rest is all arithmetic, we can calculate each cell, hence final answer. Remember no need to go fro exact answer. We now know, both statements are sufficient. Answer is C.