Quadratic Equation : Quant Question Archive [LOCKED]
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Intern
Joined: 07 Jul 2005
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16 Jul 2005, 06:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Okay, I will post without the answer so everyone can practice. (Will post answer later.) I apologize if I don't know the proper area of the forum for this, but I need help understanding how to set this up. So if you could all explain your logic, that would be great.

3x^2 (x-2) - x + 2 , x cannot equal 2
x - 2

Solve for x

When I work this out I get 3x^2(x-2)-x+2 on top, and the answer explanation seems to be able to cancel part of that out, which I don't understand.
SVP
Joined: 05 Apr 2005
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16 Jul 2005, 18:17
w07,

this expression "[3x^2 (x-2) - x + 2]/(x - 2)" should be in equation form. otherwise value of x cannot be calculated.
Manager
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18 Jul 2005, 03:34
"[3x^2 (x-2) - x + 2]/(x - 2)"= [3x^2(x-2)-(x-2)]/(x-2)=3x^2-1

does it equal 0?
Director
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18 Jul 2005, 12:56
arrived at (3X^2 - 1)......equation needed.
18 Jul 2005, 12:56
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