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Queens and Diamond

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Manager
Manager
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Joined: 29 May 2008
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Kudos [?]: 15 [0], given: 0

Queens and Diamond [#permalink] New post 16 Jun 2009, 05:25
00:00
A
B
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D
E

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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
What is the probability of drawing a queen or a diamond from a normal shuffled deck?

a) 2/3
b) 4/13
c) 17/52
d) 16/51
e) 1/4

I can't understand this questions would you please help me ?
1 KUDOS received
Current Student
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Joined: 13 May 2008
Posts: 141
Schools: LBS
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Kudos [?]: 24 [1] , given: 6

Re: Queens and Diamond [#permalink] New post 16 Jun 2009, 06:05
1
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KUDOS
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!
Manager
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Kudos [?]: 15 [0], given: 0

Re: Queens and Diamond [#permalink] New post 16 Jun 2009, 07:18
Absolutely now I got it
1 KUDOS received
Current Student
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Kudos [?]: 24 [1] , given: 6

Re: Queens and Diamond [#permalink] New post 16 Jun 2009, 07:39
1
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i don't get no kudos!!! :cry: :cry: :cry:
Senior Manager
Senior Manager
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Re: Queens and Diamond [#permalink] New post 19 Jun 2009, 20:27
One kudo for MJ2009...
Your post helped me a lot...
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Manager
Manager
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Re: Queens and Diamond [#permalink] New post 19 Jun 2009, 21:37
MJ2009 wrote:
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!


Good explanation :)
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Director
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Re: Queens and Diamond [#permalink] New post 19 Jun 2009, 22:15
Simply awesome
more because of the datailing part
+1 from me as well

MJ2009 wrote:
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!

_________________

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Re: Queens and Diamond   [#permalink] 19 Jun 2009, 22:15
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