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Question about challenge Q explanation

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Question about challenge Q explanation [#permalink] New post 17 May 2007, 10:31
The question is: "How many three-digit numbers are there, so that each is evenly divisible by 7?"

The explanation listed out 4 easy steps to find the answer:
1. Find the highest and lowest multiples within the range
2. Find the positive difference of these two numbers
3. Divide the difference by the number in the question (in this case, 7)
4. Add +1

My question is: Does this work all the time? How reliable are these steps with different questions?

Thanks for the help!

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 [#permalink] New post 17 May 2007, 10:50
it should work all the time

let's find all three digit numbers that are divisible by 9

99+9 is the lowest number =12*9
999 is the highest number =111*9
total of three digit numbers is equal to 111-12+1=100
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 [#permalink] New post 17 May 2007, 12:29
yes it will as explained by cool
  [#permalink] 17 May 2007, 12:29
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