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# Question from Challenge 6

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CEO
Joined: 15 Aug 2003
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22 Feb 2006, 08:37
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4
(A) Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
(B) Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) EACH statement ALONE is sufficient.
(E) Statements (1) and (2) TOGETHER are NOT sufficient.
Director
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22 Feb 2006, 09:53
(1) x^2 - 5x + 5 = 1 - x

(x-2)^2=0

x=2 v x=-2

(2) x^2 = 4
x=2 v x=-2

both statements lead to x=-2 as the least possible value of x
Director
Joined: 24 Oct 2005
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22 Feb 2006, 17:07
I believe D..
It is asking for least possible value.. and least possible value can be -2
_________________

Success is my only option, failure is not -- Eminem

Manager
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22 Feb 2006, 18:18
Agree with D.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4

i] x^2 - 5x + 5 = 1 - x
=> (x-2)^2=0
so x=2 ----suff

ii] x^2 = 4
=> (x-2)(x+2)=0
so x=-2,2 since -2 is smaller it is the least value here - suff
Manager
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22 Feb 2006, 18:32
good question, is not really testing math but how much you understand the tricks of the GMAT, I'll go with D as well
Senior Manager
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22 Feb 2006, 21:25
1) (x-2)^2 = 0 => x= +- 2
2) x^2=4 =>x= +- 2

both are sufficient so answer is D

Chirag
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22 Feb 2006, 21:39
Guys,
I too agree with D.
But, the least possible value from statement(1) is 2 (and not +/-2).
(x-2)^2 = 0 => x = 2 only.
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