R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.) : Quant Question Archive [LOCKED]
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# R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.)

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R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.) [#permalink]

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14 Oct 2006, 11:53
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0
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14 Oct 2006, 12:12
uphillclimb wrote:
R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0

I think 1 is sufficient

1 + 2xy + x^2y^2 = 0
(xy)^2 + 2(xy) +1 = 0
(xy + 1)^2 = 0

xy = -1.

2 is insufficient and irrelevant
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14 Oct 2006, 12:31
Agree with (A) as explained by mst
14 Oct 2006, 12:31
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