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# R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.)

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R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.) [#permalink]  14 Oct 2006, 11:53
R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0
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Re: Powerprep question [#permalink]  14 Oct 2006, 12:12
uphillclimb wrote:
R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0

I think 1 is sufficient

1 + 2xy + x^2y^2 = 0
(xy)^2 + 2(xy) +1 = 0
(xy + 1)^2 = 0

xy = -1.

2 is insufficient and irrelevant
SVP
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Agree with (A) as explained by mst
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