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Re: DS: Polygon [#permalink]
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kevincan wrote:
R is a convex polygon. Does R have at least 8 sides?

(1) Exactly 3 of the interior angles of R are greater than 80 degrees.
(2) None of the interior angles of R are less than 60 degrees.


The sum of the interion angles of the polygon = 180(n-2) where n is the number of sides in the polygon.

From (1) 180(n-2) >240
n-2 > 4/3
n>10/3
therefore n should be atleast 4 but we cannot say it is atleast 8

From(2) 180(n-2) >=60n
n-2 >= n/3
2n/3 >= 2
n >=3
we cannot say n is atleast 8

Combining both, we can still say it is atleast 4 but not 8.

Hence answer is E
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Re: R is a convex polygon. Does R have at least 8 sides? [#permalink]
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I have another way to solve this question:

(1) Exactly 3 angles are greater than 80 degrees
Let's denote "x" is the remaining sides of the polygon, then the total sides is "x+3"
The sum of interior angles = (x+3-2)*180 = (x+1)*180 degress
(a) Each of 3 angles is < 180 degrees, so sum of x remaining angles is > (x+1)*180 - 3*180 = 180x - 360 degrees
(b) However, each of the x remaining angles is <80 -> total of x angles is <80x degress
From (a) and (b) => 180x - 360 <80x
=> x<3.6
=> total sides of polygon R < 6.6 =>(1) is SUFFICIENT

(2) None of the interior angles are less than 60 degrees
(c) Let's denote "y" is the total sides of polygon R => total of angles is (y-2)*180 degrees
From (2) and (c) => (y-2)*180 >= 60y
=>120y>=360
=> y>=3
=> (2) is NOT SUFFICIENT

The answer is A
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Re: R is a convex polygon. Does R have at least 8 sides? (1) [#permalink]
IMO is E.

A convex polygon with 4 sides can still have angles greater than 80 and less than 60. Experts advice on this?
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R is a convex polygon. Does R have at least 8 sides? [#permalink]
Q: Does R have 8 sides? ==> does sum of interior angles of R = (8-2)*180 = 1080?

St 1: Provides two facts: (Exactly 3 are greater than 80)

First fact: 3 angles are > 80. The range of of the sum of these 3 angles = 3*81 -- 3*180 = 243 ---540.

Second fact: The remaining angles are all <= 80. For 5 additional angles, the range of of the sum = 5*0 -- 5*80 = 0 --- 400.

For 8 angles, the range of of the sum of all angles = range#1 + range#2 = 243 ---940. 1080 falls outside the range and therefore, it is impossible for an 8-sided polygon to have 3 sides > 80 and 5 sides <= 80.

SUFFICIENT

Statement 2: Angles are all > 60.

Range of sums for 8 angles = 8*60 --- 8*180 = 480 --- 1440. 1080 falls in this range, and accordingly an 8-sided polygon is not excluded, but in the absence of additional information it is not confirmed. In other words it is possible for an 8-sided polygon to have all angles > 60, but polygons with angles > 60 are not necessarily 8 sided.

INSUFFICIENT
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Re: R is a convex polygon. Does R have at least 8 sides? [#permalink]
Wow what a question .
Took a lot of and still got it wrong .
A is the correct answer .
It uses the property of convex polygon that every interior angle in a convex polygon is less than 180 degrees.
And the trick part in this question is to assume that the polygon is 8 sided .
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Re: R is a convex polygon. Does R have at least 8 sides? [#permalink]
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Re: R is a convex polygon. Does R have at least 8 sides? [#permalink]
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