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r, t, and s are all integers, is t/ (s^2) an integer? 1)

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r, t, and s are all integers, is t/ (s^2) an integer? 1) [#permalink] New post 10 Feb 2004, 15:24
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r, t, and s are all integers, is t/ (s^2) an integer?

1) t/rs is an integer

2) r/s is an integer

Vivek.
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 [#permalink] New post 10 Feb 2004, 15:39
1) and 2) by themselves are insufficient. From t/rs multiplied with r/s equals t/s^2 since both are integers the resulting should be an integer or C)
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 [#permalink] New post 10 Feb 2004, 15:54
C)

From 1:
Let T = 12
R = 1
S = 3
Then T/RS = 12 / 1*3 = 4 and T/S^2 = 12 / 3^2 = 12/9 = 4/3 which is not an integer
Let T = 12
R = 3
S = 1
Then T/RS = 12 / 3*1 = 4 and T/S^2 = 12 / 1^2 = 12 which IS an integer
Thus 1 is not sufficient

From 2:
Let T = 12
R = 3
S = 1
Then R/S = 3/1 = 3 and T/S^2 = 12 / 3^2 = 4/3 which is not an integer
Let T = 12
R = 2
S = 1
Then R/S = 2/1 = 2 and T/S^2 = 12 / 1^2 = 12 which IS an integer
Thus 2 is not sufficient

Combining both statements we we will always be able to get an integer by ensuring that S (R/S being an integer) is the least of the 2 divisors (T/RS being an integer). I'm not sure how to explain this but I tried a few numbers and always get T/S^2 being an integer
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 [#permalink] New post 10 Feb 2004, 23:40
Anadnk and Kpadma please explain ur proceedings!!!!!!!
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 [#permalink] New post 11 Feb 2004, 09:03
The answer is C...but I dont have the official explanation..

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 [#permalink] New post 11 Feb 2004, 09:23
mdfrahim wrote:
Anadnk and Kpadma please explain ur proceedings!!!!!!!


r, t, and s are all integers, is t/ (s^2) an integer?

1) t/rs is an integer

2) r/s is an integer


From Qustion stem: asked Is t/(s^2) an INT ?
or t = a * s^2; is "a" an INT ? --- (0)


From 1:
t/rs = b ; b= INT
t = b * rs ---- (1)

Where "b" or "r" could be either multiple of "s" or not.
If "b" or "r" is multiple of "s" ,then "a" is an INT.
If not, "a" is not an INT

INSUFF

From 2:
r/s = c; c = INT
r = c * s ---(2)

The does not give any relation between t and r&s.
INSUFF

From (1)+(2)
t= b * rs ; b = INT
r = c * s ; b = INT
togather,
t = b * c * s * s = bc * s^2
If b & c are INT, then bc = a is also INT.

SUFF

INT: Integer

Good Luck!
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 [#permalink] New post 11 Feb 2004, 11:14
Very well explained KPadma...

Vivek.
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  [#permalink] 11 Feb 2004, 11:14
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r, t, and s are all integers, is t/ (s^2) an integer? 1)

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