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# Race Winner

Author Message
TAGS:
Director
Status: Preparing for the 4th time -:(
Joined: 25 Jun 2011
Posts: 563
Location: United Kingdom
GMAT Date: 06-22-2012
GPA: 2.9
WE: Information Technology (Consulting)
Followers: 13

Kudos [?]: 375 [0], given: 217

Race Winner [#permalink]  10 Nov 2011, 14:39
00:00

Difficulty:

5% (low)

Question Stats:

40% (02:54) correct 60% (01:33) wrong based on 20 sessions
Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?

I. Stephanie II. Regine III. Brian
I only
II only
III only
I or II only
I, II, or III

Can someone please tell the approach how to solve this problem?
[Reveal] Spoiler: OA

_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610

Manager
Joined: 29 Oct 2011
Posts: 189
Concentration: General Management, Technology
Schools: Sloan '16 (D)
GMAT 1: 760 Q49 V44
GPA: 3.76
Followers: 7

Kudos [?]: 71 [2] , given: 19

Re: Race Winner [#permalink]  10 Nov 2011, 19:51
2
KUDOS
Let S, R, and B be the times that it took Stephanie, Regine, and Brian to run a 20 mile race.

From the problem: S + R = B + 2

The fastest speed was 8mph, which means the the lowest time was 20/8 = 2.5 hours, meaning that anyone who ran slower than 8mph would have finished in more than 2.5 hours.

From the equation above, you can see that B is lowest when S and R are as small as possible, and the minimum value for S and R is 2.5. So:

2.5 + 2.5 = B + 2
B = 3

The fastest (lowest) possible time for B is 3 hours, which is still slower than 2.5 hours for S and R. Therefore, either S or R could have won, but not B.
Intern
Status: Stay Hungry, Stay Foolish.
Joined: 05 Sep 2011
Posts: 41
Location: India
Concentration: Marketing, Social Entrepreneurship
GMAT 1: 650 Q V
Followers: 0

Kudos [?]: 7 [0], given: 6

Re: Race Winner [#permalink]  18 Nov 2011, 23:35
Agree with GMATmission.
The basis of assumption can be questioned in the explanation.
So,in my opinion,the winner can be anyone among I, II, III.
Director
Joined: 28 Jul 2011
Posts: 583
Location: United States
GPA: 3.86
WE: Accounting (Commercial Banking)
Followers: 1

Kudos [?]: 40 [0], given: 16

Re: Race Winner [#permalink]  19 Nov 2011, 12:10
kostyan5 wrote:
Let S, R, and B be the times that it took Stephanie, Regine, and Brian to run a 20 mile race.

From the problem: S + R = B + 2

The fastest speed was 8mph, which means the the lowest time was 20/8 = 2.5 hours, meaning that anyone who ran slower than 8mph would have finished in more than 2.5 hours.

From the equation above, you can see that B is lowest when S and R are as small as possible, and the minimum value for S and R is 2.5. So:

2.5 + 2.5 = B + 2
B = 3

The fastest (lowest) possible time for B is 3 hours, which is still slower than 2.5 hours for S and R. Therefore, either S or R could have won, but not B.

Hi kostyan5,

Can you please clarify how you have assumed S and R to be 2.5 because even B can also be 2.5 right?
if in that case anyone i.e S or R or B can win the race,please clarify on the same
_________________

Intern
Joined: 22 Nov 2011
Posts: 13
Followers: 0

Kudos [?]: 0 [0], given: 1

Re: Race Winner [#permalink]  23 Nov 2011, 09:35
I think the answer is E as we do not exactly know who is slower than the other two.
Re: Race Winner   [#permalink] 23 Nov 2011, 09:35
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