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Rainy day [#permalink] New post 13 Apr 2003, 15:18
I saw this question on the GMAT club website. Not sure whether I solved this right.

The probability that it will rain in NYC on any given day in July is 30%. what is the probability that it will rain on exactly 3 days from July 5 to July 10 ?

6C3 * (0.3*0.3*0.3*0.7*0.7*0.7) = 0.18522
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Rainy day [#permalink] New post 26 Jun 2003, 07:56
ABNY

I agree with your answer
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 [#permalink] New post 27 Jun 2003, 00:05
The initial solution was mine
BB posted this question
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 [#permalink] New post 06 Jul 2003, 19:19
Why should the answer be multiplied with 6C3?
Why not just (0.3*0.3*0.3*0.7*0.7*0.7) ?
:cry:
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 [#permalink] New post 06 Jul 2003, 22:19
The rainy days go in different order. We have to count all the combinations.
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 [#permalink] New post 07 Jul 2003, 06:14
P(rainy day ) = 0.3
P(Shiny day ) = 1 - 0.3 = 0.7

If you apply Binomial Probablity Distribution, we get
P(of getting rain on 3 days out of 6 days) = 6C3 X (0.3)3 X (0.7)3

( where (0.3)3 = 0.3X0.3X0.3 )
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Brainless

  [#permalink] 07 Jul 2003, 06:14
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