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Randomly, six people A, B, C, D, E, and F sit around a [#permalink]
24 Sep 2006, 07:26

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Difficulty:

5% (low)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

Randomly, six people A, B, C, D, E, and F sit around a circular table. What is the probability that A is in middle of B and F, B is in the middle of A and C, C is in the middle of B and D, D is in the middle of C and E, E is in the middle of D and F, F is in the middle of A and E?

Should be 1/60...Total no of arrangements=5!=120..tw possible arrangements that satisfy the condition- aniclockwise and clockwise..so 2/120=1/60...what's the answer?