I have a doubt regarding rangey^2<64y^2-64<0(y+8)(y-8)<0
If y^2 <64, then what is the range in which y exists
I want to know the steps involved in solving this. And the logic.
Thanks or the help.
Such an expression will be less than 0, if one term is negative and the other is positive. This will only happen when y is between 8 and -8 (Below -8, both terms are negative and above 8, both terms are positive)
Hence the range of y
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