Sachin9 wrote:

Bunuel/Karishma,

1) What is the range of a 1 element set?

2) say x square > 2

then root(x)> root 2

=> |x| >root 2

=>

x>root 2 and x< -ve root 2

Is this right? Kindly explain.

Yes, this is another way of putting it.

x^2 > 2This is equivalent to

|x|^2 > 2Taking square root since both sides are positive,

|x| > \sqrt{2}So

x > \sqrt{2} or

x < - \sqrt{2}Though, I feel that tackling it using inequalities is more straight forward.

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Karishma

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