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# Range of monthly salary in 1999 is 240. Range of monthly

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CEO
Joined: 15 Aug 2003
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Kudos [?]: 755 [0], given: 781

Range of monthly salary in 1999 is 240. Range of monthly [#permalink]  29 Sep 2003, 14:47
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Range of monthly salary in 1999 is 240. Range of monthly salary in 2000 is 320. What is the minimal range of the monthly salary in both 1999 and 2000?
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 6

Kudos [?]: 127 [0], given: 0

to subtract and to sum. It is helpful to draw some chart to understand.
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 6

Kudos [?]: 127 [0], given: 0

Possible variants:
(1) the two ranges are added R=560
(2) the two ranges intersect 320<R<560
(3) the small range is within the large one R=320
(4) the two ranges have the one common limit OOPS R=320 again

320?
CEO
Joined: 15 Aug 2003
Posts: 3465
Followers: 62

Kudos [?]: 755 [0], given: 781

stolyar wrote:
Possible variants:
(1) the two ranges are added R=560
(2) the two ranges intersect 320<R<560
(3) the small range is within the large one R=320
(4) the two ranges have the one common limit OOPS R=320 again

320?

Yes that is correct.

i know some basics, but i just couldnt understand how one gets 320..
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 6

Kudos [?]: 127 [0], given: 0

My approach:
say we have two sets with ranges of 10 and 20

we get the maximal range when the two ranges are as far as possible. Consider (0...10, R=10) and (100...120, R=20); R common=120

make the common R smaller (one common limit)
consider (0...10, R=10) and (10...30, R=20); R common=30

make it yet smaller (the ranges intesect)
consider (5...15, R=10) and (10...30, R=20); R common=25

make it the smallest (the larger consumes the smaller)
consider (12...22, R=10) and (10...30, R=20); R common=20

This is the minimal range. The common range of two ranges cannot be smaller than the larger one.
CEO
Joined: 15 Aug 2003
Posts: 3465
Followers: 62

Kudos [?]: 755 [0], given: 781

stolyar wrote:
My approach:
say we have two sets with ranges of 10 and 20

we get the maximal range when the two ranges are as far as possible. Consider (0...10, R=10) and (100...120, R=20); R common=120

make the common R smaller (one common limit)
consider (0...10, R=10) and (10...30, R=20); R common=30

make it yet smaller (the ranges intesect)
consider (5...15, R=10) and (10...30, R=20); R common=25

make it the smallest (the larger consumes the smaller)
consider (12...22, R=10) and (10...30, R=20); R common=20

This is the minimal range. The common range of two ranges cannot be smaller than the larger one.

This is where i get in trouble... lets say we want to find the MAXIMAL range. I thought pick the lowest in one set and pick the highest in the other set...subtract and the result is the MAXIMAL range...

but turns out i get 320 and thats the minimal range..soooo confusing.

Could you please explain how to get the maximal range?

Does anyone have tough questions on statistics and probability , anyone?

thanks
praetorian
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 6

Kudos [?]: 127 [0], given: 0

Maximal range in your question is an infinity. The smallest salary can be $0.000001 and the largest$100^[100^[100^...100]. The one thing that can be said for sure is that such an infinity is positive. However, negative salary is also possible, say a guy earns penalties only.
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