Range of monthly salary in 1999 is 240. Range of monthly : PS Archive
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# Range of monthly salary in 1999 is 240. Range of monthly

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Range of monthly salary in 1999 is 240. Range of monthly [#permalink]

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29 Sep 2003, 14:47
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Range of monthly salary in 1999 is 240. Range of monthly salary in 2000 is 320. What is the minimal range of the monthly salary in both 1999 and 2000?
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03 Oct 2003, 08:05
to subtract and to sum. It is helpful to draw some chart to understand.
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03 Oct 2003, 21:33
Possible variants:
(1) the two ranges are added R=560
(2) the two ranges intersect 320<R<560
(3) the small range is within the large one R=320
(4) the two ranges have the one common limit OOPS R=320 again

320?
CEO
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03 Oct 2003, 22:50
stolyar wrote:
Possible variants:
(1) the two ranges are added R=560
(2) the two ranges intersect 320<R<560
(3) the small range is within the large one R=320
(4) the two ranges have the one common limit OOPS R=320 again

320?

Yes that is correct.

i know some basics, but i just couldnt understand how one gets 320..
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04 Oct 2003, 02:12
My approach:
say we have two sets with ranges of 10 and 20

we get the maximal range when the two ranges are as far as possible. Consider (0...10, R=10) and (100...120, R=20); R common=120

make the common R smaller (one common limit)
consider (0...10, R=10) and (10...30, R=20); R common=30

make it yet smaller (the ranges intesect)
consider (5...15, R=10) and (10...30, R=20); R common=25

make it the smallest (the larger consumes the smaller)
consider (12...22, R=10) and (10...30, R=20); R common=20

This is the minimal range. The common range of two ranges cannot be smaller than the larger one.
CEO
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07 Oct 2003, 15:20
stolyar wrote:
My approach:
say we have two sets with ranges of 10 and 20

we get the maximal range when the two ranges are as far as possible. Consider (0...10, R=10) and (100...120, R=20); R common=120

make the common R smaller (one common limit)
consider (0...10, R=10) and (10...30, R=20); R common=30

make it yet smaller (the ranges intesect)
consider (5...15, R=10) and (10...30, R=20); R common=25

make it the smallest (the larger consumes the smaller)
consider (12...22, R=10) and (10...30, R=20); R common=20

This is the minimal range. The common range of two ranges cannot be smaller than the larger one.

This is where i get in trouble... lets say we want to find the MAXIMAL range. I thought pick the lowest in one set and pick the highest in the other set...subtract and the result is the MAXIMAL range...

but turns out i get 320 and thats the minimal range..soooo confusing.

Could you please explain how to get the maximal range?

Does anyone have tough questions on statistics and probability , anyone?

thanks
praetorian
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07 Oct 2003, 21:18
Maximal range in your question is an infinity. The smallest salary can be $0.000001 and the largest$100^[100^[100^...100]. The one thing that can be said for sure is that such an infinity is positive. However, negative salary is also possible, say a guy earns penalties only.
07 Oct 2003, 21:18
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# Range of monthly salary in 1999 is 240. Range of monthly

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