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all fractions are close to 1/3 So if we take each \(I. 47/150<50/150=1/3\) \(II. 111/330>110/330=1/3\) \(III. 299/900<300/900=1/3\) Now between II and III we can easily figure out that 299 is closer to 300 than \(47*3\). So III>I So the correct order from smallest to largest is : \(I>III>II\) So shouldn't it be B?
So the correct order from smallest to largest is : \(I>III>II\) So shouldn't it be B?
Yes, you are 100% correct. I changed this in the problem above. I said "smallest to largest", but then when I did it in my head, I put them in order from largest to smallest! Sorry about any confusion. Mike
Re: Rank those three in order from smallest to biggest. [#permalink]
19 Dec 2012, 05:28
I. 47/150 is almost 50/150 = 1/3. It is (50-47)/150 = 3/150 = 1/50 away from 1/3 II. 111/330 is beyond 110/330 = 1/3 III. 299/900 is almost 300/900 = 1/3. 299/900 is (300-299)/900 = 1/900 away from 1/3
I is the farther to the left of 1/3 than III while II is the largest.