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Rate problem [#permalink] New post 07 Sep 2011, 11:47
if a car had traveled 20 kmh faster than it actualy did, the trip would have lasted 30 minutes less. If the car went exactly 60km, at what speed did it travel?

35 kmh
40 kmh
50 kmh
60 kmh
65 kmh

Answer is B, given by the following equation:

60/x = 60/x+20 + 0.5 ; backsolving with 40 does it.

Is there a better way to solve this?
Manager
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Re: Rate problem [#permalink] New post 07 Sep 2011, 12:22
alexmarcuk wrote:
if a car had traveled 20 kmh faster than it actualy did, the trip would have lasted 30 minutes less. If the car went exactly 60km, at what speed did it travel?

35 kmh
40 kmh
50 kmh
60 kmh
65 kmh

Answer is B, given by the following equation:

60/x = 60/x+20 + 0.5 ; backsolving with 40 does it.

Is there a better way to solve this?



quite honestly, comparing for times or speeds is the easiest method in distance-speed-time problems..
if your not very comfortable, another alternatively easy method is substitution..

i tried the substitution technique and nailed the ans in about 45 sec
Re: Rate problem   [#permalink] 07 Sep 2011, 12:22
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