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Rate Problem... Really good question [#permalink] New post 01 Apr 2006, 22:43
Hi guys,

I recently went to a Kaplan practice exam which was not so great as it was a paper test but it was free so can't complain but here is a question I came across which I had a problem with. Let me know if anyone an figure it out.

Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

a. 19
b. 28
c. 30
d. 32
e. 44


I'll post the answer a little later so everyone has a fair chance to answer.
:)
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 [#permalink] New post 02 Apr 2006, 00:54
Answer C...

Steve travels at a rate of 57 floors/60s~1floor/1s

Joyce travels at a rate of 63 floors/60s~1floor/1s

Between them there are approximatelly 40 floors, so they will both have to travel ~ 20 floors to cross each other.... 20 floors is ~ 20 s

We need to use this formula.... Rate*Time=Distance

Steve: 57/60*20=19

Joyce: 63/60*20=21....

Adding things up we get 30......
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 [#permalink] New post 02 Apr 2006, 01:12
Yeah C

Usuing Speed Formula: Speed = Distance / Time

Distance to be covered = 51-11 = 40

Speed of approach = 57 + 63 floors/min

Time = 40/120 = 1/3

So Steve will cover 57x 1/3 floors in that time = 19

So he will be in 19 + 11 floor = 30th Floor
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 [#permalink] New post 02 Apr 2006, 19:32
yeap its 30 i kinda figured it out ina different way little later because it was bothering me...

but its pretty much the same :)
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  [#permalink] 02 Apr 2006, 19:32
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