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The number of stamps that Kaye and Alberto had respectively were in the ratio 5:3. After Kaye gave Alberto 10 of her stamps, the ratio went to 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

The number of stamps that Kaye and Alberto had respectively were in the ratio 5:3. After Kaye gave Alberto 10 of her stamps, the ratio went to 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

You have 2 equations with 2 variables, so you can solve for K and A.
A=90 and K=150. But the question asks for the number of stamps as a result of the gift:
A+10 = 100
K-10 = 140
-> Kaye had 40 more stamps than Alberto

If m, r, x, and y are positive, is the ratio of m:r = the ratio of x:y?

(1) The ratio of m to y is equal to the ratio of x to r
(2) The ratio of m + x to r + y is equal to the ratio of x to y

Solution:

(1) if m=1, y=2, x=1, r=2 (complies to the condition m/y=x/r) then
m/r=x/y
BUT if m=5, y=15, x=1, r=3 (also complies to the condition m/y=x/r)
then m/r<>x/y ---> Not sufficient

(2) if x/y = (m+x)/(r+y) then x/y = m/r
You can try any selection of values for x,y,m, and r
e.g. x=5, y=20, m=1, r=4
---> Sufficient

The number of stamps that Kaye and Alberto had respectively were in the ratio 5:3. After Kaye gave Alberto 10 of her stamps, the ratio went to 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

Assuming initial ratio co-efficient as x and it is y afterwards so initially kaye and alberto had 5X and 3X stamps respectively. After the exchange, they had 7Y and 5Y stamps respectively. since kaye gave 10 to Alberto,it can be derived that 5X-7Y=10 & 5Y-3X =10

from the above equations Y =20 and X=30 so Kaye had 60 more stampsearlier and 40 more stamps after exchange

If m, r, x, and y are positive, is the ratio of m:r = the ratio of x:y?

(1) The ratio of m to y is equal to the ratio of x to r
(2) The ratio of m + x to r + y is equal to the ratio of x to y

from 1 => m/y =x/r which doesn't give the answer of question
from 2 => m+x/r+y =x/y =>my+xy = rx +xy => my =rx so m/r =x/y

and it answers the question so i would go with B

there is a standard theorem also that if a/b =c/d then both are equal to a+c/b+d here it is given that a/b =a+b/c+d which is only possible when a/b =c/d

It has been a fairly long time since I have posted here, but I definitely did not want to sign off without giving readers a quick update on my personal...