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# Ratios and Percents - Employee salaries

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Ratios and Percents - Employee salaries [#permalink]  09 Oct 2009, 20:59
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Question Stats:

50% (02:06) correct 50% (01:43) wrong based on 1 sessions
Can't seem to figure this one out.

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Re: Ratios and Percents - Employee salaries [#permalink]  09 Oct 2009, 22:06
On July 1 of last year, total employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the average employee salary was 10% more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 of last year?

# of employees before July 1 - x;
# of employees after July 1 - 0.9x;

Average salary before July 1 - y;
Average salary after July 1 - 1.1y;

Total salary before July 1 - xy;
Total salary after July 1 - 1.1*0.9*xy=0.99xy --> \frac{0.99xy}{xy}*100=99%.

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problem help [#permalink]  09 May 2010, 19:22
on july 1 0f last year, the total # of employees at company E was decreased by 10%. Without any change in salaries of the remainong employees, the avarage (arthmetic mean) employee salary was 10 % more after the decrease in number of employees than before the decrease. the total of the compained salaries of all of the employees at Company E afterjulay 1 last year was what percent of that before julay 1 last year?
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Re: Ratios and Percents - Employee salaries [#permalink]  19 May 2010, 20:26
Bunuel wrote:
On July 1 of last year, total employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the average employee salary was 10% more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 of last year?

# of employees before July 1 - X
# of employees after July 1 - 0.9X

Average salary before July 1 - Y
Average salary after July 1 - 1.1Y

Total salary before July 1 - XY
Total salary after July 1 - 1.1*0.9*XY=0.99XY --> (1.1*0.9*XY)/XY*100=99%

Bunuel, I would disagree with you here ....the question said that there was no decrease in the salary of other employees but you wrote 1.1Y ...shouldnt it still be Y after the change ?
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Re: Ratios and Percents - Employee salaries [#permalink]  20 May 2010, 02:29
dimitri92 wrote:
Bunuel wrote:
On July 1 of last year, total employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the average employee salary was 10% more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 of last year?

# of employees before July 1 - X
# of employees after July 1 - 0.9X

Average salary before July 1 - Y
Average salary after July 1 - 1.1Y

Total salary before July 1 - XY
Total salary after July 1 - 1.1*0.9*XY=0.99XY --> (1.1*0.9*XY)/XY*100=99%

Bunuel, I would disagree with you here ....the question said that there was no decrease in the salary of other employees but you wrote 1.1Y ...shouldnt it still be Y after the change ?

"the average employee salary was 10% more after the decrease in the number of employees than before the decrease."
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Re: Question Help [#permalink]  07 Dec 2010, 19:01
dc123 wrote:
On july 1st of last year, the total number of employees at company E was decreased by 10%. Without any change in the salaries of the remaining employees, the avg employee salary was 10% more after the decrease in number of employees that before the decrease. The total combine salaries of all the employees at company E after July 1 last year was what percent of the before july 1 of last year?

90%

99%

100%

101%

110%

Help plz....

Question with percentages and answer also in percentages. The first and only thing I want to do is assume values.

Initial total no of emp = 100 (assumed value)
Initial total salary = 100 (assumed value)
Initial average = $1/emp (100/100 = 1) New total no of emp = 90 (10% decrease) New average salary =$1.1/emp (10% increase)
New total salary = 90*1.1 = 99
So new total salary is 99% of initial total salary.
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Re: Question Help   [#permalink] 07 Dec 2010, 19:01
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