Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 07:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Remainder

Author Message
TAGS:
Senior Manager
Joined: 08 Aug 2005
Posts: 251
Followers: 1

Kudos [?]: 17 [0], given: 0

Remainder [#permalink]  24 Nov 2005, 01:20
If k^4 is divisible by 32, which of the following could be the remainder when k is divided by 32?

(1). 2
(2). 4
(3). 6
Director
Joined: 14 Sep 2005
Posts: 994
Location: South Korea
Followers: 2

Kudos [?]: 44 [0], given: 0

if k = 2, k^4 = 16 (not divisible by 32)
if k = 4, k^4 = 256 (divisible 32)
if k = 6, k^4 = 1296 (not divisible by 32)

Thus only 4 can be the remainder.
_________________

Auge um Auge, Zahn um Zahn !

Director
Joined: 13 Nov 2003
Posts: 793
Location: BULGARIA
Followers: 1

Kudos [?]: 27 [0], given: 0

32=2^5 so if 8^4=2^12=2^5x2^5x2^2 is divided by 2^5 it will have reminder 2^2 or 4
SVP
Joined: 28 May 2005
Posts: 1743
Location: Dhaka
Followers: 6

Kudos [?]: 72 [0], given: 0

gamjatang wrote:
if k = 2, k^4 = 16 (not divisible by 32)
if k = 4, k^4 = 256 (divisible 32)
if k = 6, k^4 = 1296 (not divisible by 32)

Thus only 4 can be the remainder.

agreed. 4 should be the answer.
_________________

hey ya......

SVP
Joined: 24 Sep 2005
Posts: 1893
Followers: 11

Kudos [?]: 139 [0], given: 0

Re: Remainder [#permalink]  24 Nov 2005, 01:36
getzgetzu wrote:
If k^4 is divisible by 32, which of the following could be the remainder when k is divided by 32?

(1). 2
(2). 4
(3). 6

let k= 32m + r ( r is the remainder)
k^4= ( 32m+r)^4 ...we know if spreading this expresion we'll get only one term which is not a multiple of 32m ...that is r^4
since k^4 is divisible by 32 ----> r^4 must be divisible by 32
try those choices provided...only 4 satisfies.
4 is correct.
Senior Manager
Joined: 08 Aug 2005
Posts: 251
Followers: 1

Kudos [?]: 17 [0], given: 0

Laxi your responses are stunning! You make things just way too simple! I am absolutely overawed. And Thank You so much.....
Director
Joined: 14 Sep 2005
Posts: 994
Location: South Korea
Followers: 2

Kudos [?]: 44 [0], given: 0

getzgetzu wrote:
Laxi your responses are stunning! You make things just way too simple! I am absolutely overawed. And Thank You so much.....

getzgetzu/ You may join us. We have a fan club for Laxi.
_________________

Auge um Auge, Zahn um Zahn !

Senior Manager
Joined: 08 Aug 2005
Posts: 251
Followers: 1

Kudos [?]: 17 [0], given: 0

And you are no less great than her gamjatang......
SVP
Joined: 24 Sep 2005
Posts: 1893
Followers: 11

Kudos [?]: 139 [0], given: 0

getzgetzu wrote:
And you are no less great than her gamjatang......

yes,o bba is great
Similar topics Replies Last post
Similar
Topics:
Remainder 4 15 May 2009, 08:37
remainder 22 23 Jul 2008, 04:34
Remainders 4 15 May 2008, 17:16
3 When x is divided by 5, the remainder is 2. Is x divisible 2 27 Jan 2008, 10:32
Remainder 4 05 Jul 2006, 10:38
Display posts from previous: Sort by