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CEO
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represents the remainder of 3x/2, which of the following [#permalink]
 12 Sep 2003, 04:04
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[x] represents the remainder of 3x/2, which of the following
expression is equal to 1:
a. [2x] b. [3x]+1 c. [2x] +1
I dont have the official answer to this one..
i m having a hard time interpreting this.
prat
Last edited by Praetorian on 13 Sep 2003, 21:07, edited 1 time in total.
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Senior Manager
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Interesting question.
[X] represents remainder of number 3x/2
Now, question asks which of the following is equal to 1.
Now, 3[x] + 1 represents remainder of number: 3(3x)/2 + 1 {replacing value of [x]}
=>i.e. remainder of 9x/2 + 1
9x/2 will have remainder either 1 or 0
Thus, 9x/2 + 1 will have only 1 as remainder.
Why?
when 9x/2 has remainder 0 => 9x/2 + 1 has remainder 1
9x/2 has remainder 1=> 9x/2 + 1 has remainder 0
For choice A, number is 0.
choice B, number is 0 or 1.
choice C, number is 1 or 3.
- Vicks
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Senior Manager
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I guess answer would be [2x]+1 , but is not among the choices 
IMO all others are different than 1
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CEO
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MartinMag wrote: I guess answer would be [2x]+1 , but is not among the choices IMO all others are different than 1 Martin
your answer choice is there...but can you explain please?
thanks
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Senior Manager
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praetorian123 wrote: MartinMag wrote: I guess answer would be [2x]+1 , but is not among the choices IMO all others are different than 1 Martin your answer choice is there...but can you explain please? thanks 2[x]+1 would throw a different answer than [2x]+1
[2x]+1 is not there 
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CEO
Joined: 15 Aug 2003
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MartinMag wrote: praetorian123 wrote: MartinMag wrote: I guess answer would be [2x]+1 , but is not among the choices IMO all others are different than 1 Martin your answer choice is there...but can you explain please? thanks 2[x]+1 would throw a different answer than [2x]+1 [2x]+1 is not there Hey martin
Its right there 
no, actually my question had a typo...
Sorry about that guys!
[2x] will have a remainder of 0...
so.. obviously we need [2x] + 1..
thanks
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answer is c I guess... Although depending on what x is, b could be valid too...
case a:
[2x] is the remainder of 3(2x)/2. The fraction resolves itself quite nicely to 3x, so there is no remainder. [2x]=0.
case b:
[3x] is the remainder of 3(3x)/2. This fraction may or may not have a remainder, depending on what x is. If x=2, then [3x]+1 = 1. If x=7, then [3x]+1=1+1=2
case c:
looking at (a) above, [2x]=0, so [2x]+1=1.
definitely c, and maybe b depending on the value of x...
oops, just read the answers but don't understand... did you fix your typo in the question prat?
regards,
Maniaque
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CEO
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Maniaque27 wrote:
definitely c, and maybe b depending on the value of x...
regards,
Maniaque
Hey
yes, i did correct the typo
The very fact that you can have 1 or 2 as remainder makes B invalid..
We are looking for the best answer..remember
thanks
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