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Richard has 3 Green, 2 Red, 3 Blue balls in a bag. He

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Richard has 3 Green, 2 Red, 3 Blue balls in a bag. He [#permalink] New post 22 Jan 2005, 21:36
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Richard has 3 Green, 2 Red, 3 Blue balls in a bag. He randomly picks 5 from the bag without replacement. What is the probability that out of the 5 balls drawn, he has picked 1 Red, 2 Green and 2 Blue balls.
(This is a 48+ problem, Hypogeometric.)
a) 8/28
b) 9/28
c) 10/28
d) 10/18
e) 11/18
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 [#permalink] New post 22 Jan 2005, 21:47
It's (b), right? I kind of have forgotten how to do combinations a little.
  [#permalink] 22 Jan 2005, 21:47
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Richard has 3 Green, 2 Red, 3 Blue balls in a bag. He

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