Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 03:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Right triangle PQR is to be constructed in the xy-plane so

Author Message
TAGS:
Manager
Joined: 30 Jan 2006
Posts: 146
Followers: 1

Kudos [?]: 9 [0], given: 0

Right triangle PQR is to be constructed in the xy-plane so [#permalink]  15 Apr 2006, 20:01
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parallel to the x-axis. The x- and y-coordinates of P, Q, and R are to be integers that satisfy the inequalities -4 =< x =< 5 and 6 =< y =< 16. How many different triangles with these properties could be constructed?
VP
Joined: 21 Sep 2003
Posts: 1066
Location: USA
Followers: 3

Kudos [?]: 39 [0], given: 0

This is a Q. My guess is

(9*10)*(10*11) --> Assuming there is no restriction that x co-ordinate of P must be > x co-ordinate of Q.

For each base and height chosen, there are (5+4)*(16-6) = 9*10 triangles possible.

Also there are:
1) 11 bases (PR) and to choose from (y=6 through y = 16, both included).
2) 10 heights (QR) to choose from (x=-4 through x = 5, both included)

Total = 9*10*10*11?
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

Manager
Joined: 30 Jan 2006
Posts: 146
Followers: 1

Kudos [?]: 9 [0], given: 0

Absolutely correct

Answer is 9900, which you have given above.
Senior Manager
Joined: 08 Sep 2004
Posts: 258
Location: New York City, USA
Followers: 1

Kudos [?]: 9 [0], given: 0

giddi77 wrote:
This is a Q. My guess is

(9*10)*(10*11) --> Assuming there is no restriction that x co-ordinate of P must be > x co-ordinate of Q.

For each base and height chosen, there are (5+4)*(16-6) = 9*10 triangles possible.

Also there are:
1) 11 bases (PR) and to choose from (y=6 through y = 16, both included).
2) 10 heights (QR) to choose from (x=-4 through x = 5, both included)

Total = 9*10*10*11?

Great Solution.
Similar topics Replies Last post
Similar
Topics:
Right triangle PQR is to be constructed in the xy-plane so 1 01 Apr 2008, 11:19
Right triangle PQR is to be constructed in the xy-plane so 2 02 Mar 2008, 13:11
Right triangle PQR is to be constructed in the xy-plane so 1 26 Feb 2008, 18:51
Right triangle PQR is to be constructed in the xy-plane so 16 24 Jun 2007, 20:29
1 Right triangle PQR is to be constructed in the xy-plane so 6 07 Aug 2006, 17:31
Display posts from previous: Sort by