This is a

Q. My guess is

(9*10)*(10*11) --> Assuming there is no restriction that x co-ordinate of P must be > x co-ordinate of Q.

For each base and height chosen, there are (5+4)*(16-6) = 9*10 triangles possible.

Also there are:

1) 11 bases (PR) and to choose from (y=6 through y = 16, both included).

2) 10 heights (QR) to choose from (x=-4 through x = 5, both included)

Total = 9*10*10*11?

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