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Robots X, Y, and Z each assemble components at their

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Robots X, Y, and Z each assemble components at their [#permalink] New post 03 Jan 2011, 18:30
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Robots X, Y, and Z each assemble components at their respective constant rates. If r(x) is the ratio of robot X's constant rate to robot Z's constant rate and r(y) is the ratio of robot Y's constant rate to robot Z's constant rate, is robot Z's constant rate the greatest of the three?

(1) r_x<r_y
(2) r_y<1

Can some explain the reasoning behind this ques.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 08 Feb 2012, 05:09, edited 1 time in total.
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Re: Robots X, Y, and Z each assemble [#permalink] New post 08 Feb 2012, 05:06
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Robots X, Y, and Z each assemble components at their respective constant rates. If r(x) is the ratio of robot X's constant rate to robot Z's constant rate and r(y) is the ratio of robot Y's constant rate to robot Z's constant rate, is robot Z's constant rate the greatest of the three?

Let the rates of robots X, Y, and Z be x, y, and z respectively. Given: r_x=\frac{x}{z} and r_y=\frac{y}{z}. Question is z>x and z>y?

(1) r_x<r_y --> \frac{x}{z}<\frac{y}{z} --> x<y. Not sufficient.

(2) r_y<1 --> \frac{y}{z}<1 --> y<z. Not sufficient.

(1)+(2) As x<y and y<z then x<y<z. Sufficient.

Answer: C.
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Re: Robots X, Y, and Z each assemble components at their [#permalink] New post 07 May 2013, 07:09
Does this equation work when plugging in numbers, opposed to looking at pure variables?
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Re: Robots X, Y, and Z each assemble components at their [#permalink] New post 07 May 2013, 14:10
laythesmack23 wrote:
Does this equation work when plugging in numbers, opposed to looking at pure variables?


Sure. Lets say the rates are X = 5, Y = 6 and Z = 7.

Y/Z = 6/7 -> as stated in II

X/Y = 5/6 and Y/Z = 6/7 -> 5/6< 6/7 as stated in I


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Re: Robots X, Y, and Z each assemble components at their   [#permalink] 07 May 2013, 14:10
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