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Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
28 Dec 2009, 12:18
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Question Stats:
76% (02:55) correct
24% (02:27) wrong based on 399 sessions
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
Re: Method of Allegation in Percentages [#permalink]
28 Dec 2009, 12:25
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gaurav05nov wrote:
Guys, please help me out. I want to know how to solve this question using the Allegation method. I know the other way(using equations) but I need to understand the Allegation method.
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
Re: Method of Allegation in Percentages [#permalink]
28 Dec 2009, 14:35
Bunuel, thanks for the solution but as i said, i already know the "equations" method. The problem is that I cant solve it using the Allegation method. Any help on that would be nice.
Re: Method of Allegation in Percentages [#permalink]
13 Jul 2010, 04:48
I want to respond to the following question appearing in this forum: _____ Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
A) n/6 B) n/3 C) 3n/5 D) 5n/6 E) 8n/5 _____
The answer C) 3n/5 for Gin is obviously not correct for the following reason. Gin's concentration is 60% which is much higher than that of Vermouth (40%). Obviously, you need less of Gin than Vermouth to make n quantity of Martin. Consequently, the answer we should be looking for must be below 1/2 of the quantity of the total (n). The correct proportional volume of Gin is 3n/10 using the Alligation Method. Make a nine cell table like the one below (Unfortunately, I can't draw the table here. I have added starred lines to space the figures to create a Table image). Obtain diagonal differences and enter them as shown in top right and bottom right boxes(always positive numbers). Add right hand column (15+35=50). Calculate amount of Gin proportion as (n/50)*15 =3/10 n. Calculate amount of Vermouth proportion as (n/50)*35 =7/10 n
Re: Method of Allegation in Percentages [#permalink]
22 Jul 2011, 04:02
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Dear Friends,
Using allegations we will view the action that Rodrick performs as below:
"He will Mix Martini [60 % gin by volume ] with Gin [ 100 % gin by volume] to yield a martini [75 % gin by volume]."
By the method of allegations : If we have 2 quantities to mix ,one with higher percentage H and other with lower percentage L ,to get a desired solution R %we proceed as Percentage of Lower in final Result = H-R Percentage of Higher in final Result = R-L.
Therefore using the allegations method we have %volume of Pure Gin required = 75 -60 = 15 %volume of Martini (60 % gin)required = 100 -75 =25
Which reduces to Pure Gin to Martini =3 :5. Which can be inferred as for every 5 ml of martini if we should add 5 ml of pure gin to get a drink that is 75 % gin and 25 % Vermouth by volume.
So , we have : For 5 ml Martini we need 3 ml Gin For 1 ml martini we need 3/5 ml of Gin For 'n' ml of martini we need 3n/5 ml of Gin.
Re: Method of Allegation in Percentages [#permalink]
18 Sep 2011, 00:45
Bunuel wrote:
gaurav05nov wrote:
Guys, please help me out. I want to know how to solve this question using the Allegation method. I know the other way(using equations) but I need to understand the Allegation method.
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
Re: Method of Allegation in Percentages [#permalink]
18 Sep 2011, 08:02
2
This post received KUDOS
total V G 1 ounce 0.4 0.6
n ounce 0.4n 0.6n -------------initial expression
lets say g ounces of gin is added to this mixture
n+g 0.4n 0.6n+g --------------final expression
given that after adding g ounces of gin , V should become 25% of the total volume.
=>Volume of V/total volume = 25/100
=> 0.4n /n+g = 1/4
=> 1.6n = n+g
=> g = 3n/5
Answer is C.
petrifiedbutstanding wrote:
Bunuel wrote:
gaurav05nov wrote:
Guys, please help me out. I want to know how to solve this question using the Allegation method. I know the other way(using equations) but I need to understand the Allegation method.
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
Re: Method of Allegation in Percentages [#permalink]
19 Sep 2011, 02:29
2
This post received KUDOS
Expert's post
gaurav05nov wrote:
Guys, please help me out. I want to know how to solve this question using the Allegation method. I know the other way(using equations) but I need to understand the Allegation method.
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
He wants to mix a martini of 60% Gin with a liquid that is 100% Gin to give a mixture with 75% Gin (because 25% is Vermouth) Using the mixtures formula discussed here (http://www.veritasprep.com/blog/2011/03 ... -averages/), we get, w1/w2 = (100 - 75)/(75 - 60) = 5:3 Martini:Pure Gin must be added in the ratio 5:3. So if martini is n, pure gin must be (3/5)n
Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
09 Sep 2013, 00:30
1
This post received KUDOS
gaurav05nov wrote:
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
A) n/6 B) n/3 C) 3n/5 D) 5n/6 E) 8n/5
Initially Martini = V : G = 4 : 6 = 2 : 3 Ratio required is = 25 : 75 = 1 : 3 Since V is same hence ratio should be 2 : 6 Hence 3 parts of gin should be added to the initial mixture i.e. same as what was in the initial mixture i.e. 60n/100 = 3n/5
The mixture related problems if dealt with ratios becomes much easier..
Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
16 Dec 2013, 05:52
1
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gaurav05nov wrote:
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
13 Jan 2015, 06:27
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Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
13 Jan 2015, 06:50
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PROBLEM: Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
A) n/6 B) n/3 C) 3n/5 D) 5n/6 E) 8n/5
SOLUTION:
A quick way to calculate without any algebra is:
(Old - New)/(New) i.e. (40-25)/(25) = 3/5 i.e. Martini should be diluted 3/5 times
Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
30 Dec 2015, 06:12
HI Karishma
Is this approach also right (from one of your posts)?
Volume (initial) x concentration (initial) = Volume (final) x Concentration (final) Since, the volume of Vermouth remains same (not Gin), this should be applied to Vermouth Therefore, n x 40% = Volume (final) x 25% Volume (final) = 8n/5
So, solution added = (8n/5) - n ==> 3n /5
VeritasPrepKarishma wrote:
gaurav05nov wrote:
Guys, please help me out. I want to know how to solve this question using the Allegation method. I know the other way(using equations) but I need to understand the Allegation method.
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?
He wants to mix a martini of 60% Gin with a liquid that is 100% Gin to give a mixture with 75% Gin (because 25% is Vermouth) Using the mixtures formula discussed here (http://www.veritasprep.com/blog/2011/03 ... -averages/), we get, w1/w2 = (100 - 75)/(75 - 60) = 5:3 Martini:Pure Gin must be added in the ratio 5:3. So if martini is n, pure gin must be (3/5)n
Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]
30 Dec 2015, 22:26
1
This post received KUDOS
Expert's post
madhusudhan237 wrote:
HI Karishma
Is this approach also right (from one of your posts)?
Volume (initial) x concentration (initial) = Volume (final) x Concentration (final) Since, the volume of Vermouth remains same (not Gin), this should be applied to Vermouth Therefore, n x 40% = Volume (final) x 25% Volume (final) = 8n/5
So, solution added = (8n/5) - n ==> 3n /5
Yes, correct. Since amount of Vermouth stays the same in the two cases, Volume of solution*Concentration of Vermouth should be equal in the two cases. _________________
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