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Root(80)+root(125)

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Root(80)+root(125) [#permalink] New post 01 Oct 2012, 05:02
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93% (01:30) correct 6% (00:16) wrong based on 92 sessions
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Re: Root(80)+root(125) [#permalink] New post 01 Oct 2012, 05:03
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Re: Root(80)+root(125) [#permalink] New post 01 Oct 2012, 07:43
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Whe we deal with this problems may be the best thing to do is to break the number into factors

\sqrt{80}=\sqrt{2*5*2*2*2} ---> \sqrt{4*4*5} ---> 4\sqrt{5}

\sqrt{125} = \sqrt{25 *5} -----> 5 \sqrt{5}

4\sqrt{5} + 5 \sqrt{5} = 9\sqrt{5}

A should be the answer
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Re: Root(80)+root(125) [#permalink] New post 01 Oct 2012, 19:42
Answer is A (Same explanation as Carcass's)
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Re: Root(80)+root(125) [#permalink] New post 04 Oct 2012, 00:50
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\sqrt{80} = \sqrt{16*5} = 4\sqrt{5} ........(1)

\sqrt{125} = \sqrt{25*5} = 5\sqrt{5} .......(2)

Thus 4\sqrt{5} + 5\sqrt{5} = 9\sqrt{5}

Thus answer is A
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Re: Root(80)+root(125) [#permalink] New post 04 Oct 2012, 13:59
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Re: Root(80)+root(125) [#permalink] New post 05 Oct 2012, 04:46
.
sqt80=4sqrt5
sqrt125=5sqrt5

total = 9sqrt5
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Re: Root(80)+root(125) [#permalink] New post 06 Oct 2012, 10:24
\sqrt{80} + \sqrt{125}

\sqrt{2x2x2x2x5} + \sqrt{5x5x5}

4\sqrt{5} + 5\sqrt{5}

\sqrt{5} ( 4+5)

9\sqrt{5}

Ans: A
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Re: Root(80)+root(125)   [#permalink] 06 Oct 2012, 10:24
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