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Check highlighted portion, when u took out 2^3 , outside the root, basically you left inside only 2^2. However in highlighted portion, you marked it as 2^4 and hence the wrong answer. _________________

Root of (16*20+8*32)= [#permalink]
28 Feb 2015, 17:52

Expert's post

Hi soniasawhney,

You CAN factor out a 4, but I'd like to see your work so that we can assess whether you're factoring out that 4 correctly or not. So, can you post your work/"steps"?

As an aside, after factoring out a 4, you'd then have more work to do to get to the solution.

Re: Root of (16*20+8*32)= [#permalink]
01 Mar 2015, 12:27

This is how I was doing it..

4[(4*5)+(2*8)] 4[20+16] 4[36] take the square root... (2)(6)=12

However, I now realize that the way I was factoring it, I actually was taking out 'too many' 4's and I should have done it like so...is this right? 4[(16*5)+(8*8)] 4[80+64] 4[144] take the square root... 2*12=24

Re: Root of (16*20+8*32)= [#permalink]
01 Mar 2015, 13:52

1

This post received KUDOS

Expert's post

Hi soniasawhney,

As you've come to realize, you have to be careful when factoring out numbers from large calculations.

There are actually several different ways to 'factor down' and simplify this question, but your second approach is correct (and is just as valid as any other).

Here's another way to do it (based on the same ideas that you were using):

You might catch that 16 is a factor of BOTH terms (16x20 and 8x32). By factoring out 16, we can simplify the calculation even further....

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