The equation y-(5/y-3)=3-(5/y-3) has:
A) an infinite number of roots, all of them real
B) exactly two roots, both nonintegral
C) exactly two roots, both integral
D) exactly one root, which is integral
E) no roots
I get 3 for a root (D), but ans is E?
3 can't be a root because if you substitute 3 for y you get undefined because the denominator is (y-3)