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roots of equation

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Intern
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Joined: 09 Nov 2009
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roots of equation [#permalink] New post 11 Nov 2009, 08:22
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A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (01:03) wrong based on 1 sessions
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The equation y-(5/y-3)=3-(5/y-3) has:

A) an infinite number of roots, all of them real
B) exactly two roots, both nonintegral
C) exactly two roots, both integral
D) exactly one root, which is integral
E) no roots


I get 3 for a root (D), but ans is E?
VP
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Re: roots of equation [#permalink] New post 11 Nov 2009, 08:34
elinka wrote:
The equation y-(5/y-3)=3-(5/y-3) has:

A) an infinite number of roots, all of them real
B) exactly two roots, both nonintegral
C) exactly two roots, both integral
D) exactly one root, which is integral
E) no roots


I get 3 for a root (D), but ans is E?


3 can't be a root because if you substitute 3 for y you get undefined because the denominator is (y-3)
Manager
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Re: roots of equation [#permalink] New post 11 Nov 2009, 14:46
lagomez wrote:
elinka wrote:
The equation y-(5/y-3)=3-(5/y-3) has:

A) an infinite number of roots, all of them real
B) exactly two roots, both nonintegral
C) exactly two roots, both integral
D) exactly one root, which is integral
E) no roots


I get 3 for a root (D), but ans is E?


3 can't be a root because if you substitute 3 for y you get undefined because the denominator is (y-3)


Yes that is precisely why the equation doesn't have any roots. Hence, answer is
"E"
Manager
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Re: roots of equation [#permalink] New post 12 Nov 2009, 02:18
Could someone confirm OA please?
Re: roots of equation   [#permalink] 12 Nov 2009, 02:18
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