praetorian123 wrote:

Rules

1. Time yourself

2. Work your solution on a seperate sheet of paper

3. write your solution here , and your time please

I say it again, we request your timings for different problems. this will help us in our project. you can just say >2 min or <2 min...something like that.

How many four letter distinct initials can be formed using the alphabets of English language such that the last of the four words is always a consonant?

[ Consonant => all aphabets except the vowels A,E,I,O and U ]

1) (26^3)*(21)

2) 26*25*24*21

3) 25*24*23*21

4) 25^3*21

Edit: thanks kpadma, the correction has been done.

1) 26^3 * 21 is the answer. Good Discussion guys.

The question asks you to find out the number of distinct initials and not initials where the letters are distinct.

anandnk, is that clear now?

First letter can be arranged in 26 ways

Second letter can be arranged in 26 ways

Third letter can be arrranged in 26 ways

last one...NO vowels...so 26- 5 =21 ways

26^3 * 21 ways

Answer A

thanks all

praetorian