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# Rules 1. Time yourself 2. Work your solution on a seperate

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CEO
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Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]

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10 Mar 2004, 19:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Rules

1. Time yourself
2. Work your solution on a seperate sheet of paper

If the square root of the product of three distinct positive
integers is equal to the largest of the three numbers, what is the
product of the two smaller numbers?

(1) The largest number is 12.
(2) The average (arithmetic mean) of the three numbers is 20/3
Director
Joined: 03 Jul 2003
Posts: 652
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10 Mar 2004, 19:58
Ans: D

Time more than 4 mins
Manager
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10 Mar 2004, 20:58
I think it it is A..2 min
Manager
Joined: 28 Jan 2004
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10 Mar 2004, 22:50
I will go for A (only statement 1 can be used to answer).
Time taken 30 seconds.

Sol. Three integers be X,Y,Z and largest be Z.
sqrt(XYZ) = Z ,replace Z by 12
sqrt(XY*12) = 12
or sqrt(XY) = sqrt(12)
or XY = 12
Director
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11 Mar 2004, 02:40
Agree with mantha and mdfrahim, think that the answer is A)
Time: 2,5 min.
SVP
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11 Mar 2004, 04:42
a) sqrt( a * b * 12 ) = 12
so a * b = 12
Sufficient
b) a+b+c = 20
Only number that satisfies this and a * b = c is c = 12
Sufficient
< 2 minutes
CEO
Joined: 15 Aug 2003
Posts: 3460
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Kudos [?]: 862 [0], given: 781

Re: [#18] 2 Min. Challenge : Product [#permalink]

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11 Mar 2004, 05:30
praetorian123 wrote:
Rules

1. Time yourself
2. Work your solution on a seperate sheet of paper

If the square root of the product of three distinct positive
integers is equal to the largest of the three numbers, what is the
product of the two smaller numbers?

(1) The largest number is 12.
(2) The average (arithmetic mean) of the three numbers is 20/3

D is correct

good work anand
Senior Manager
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11 Mar 2004, 05:51
I agree with Anandnk and Kpadma.

The only distinct positive integers that satisfy the requirement that their sum = 20, and that the largest integer = the product of the other 2 integers are 6, 2 and 12.

If you try other combinations, you'll find that they don't sum to 20. Example: a=3; b=4 ; ab = c = 12 but 3 + 4 + 12 <> 20. Same with 8, 2 and 16.
11 Mar 2004, 05:51
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