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Running at the same constant rate, 6 identical machines can

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Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

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Question: 23
Page: 155
Difficulty: 600
[Reveal] Spoiler: OA

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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SOLUTION

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

6 machines produce 270 bottles per minute;
1 machine produces 270/6=45 bottles per minute;
10 machines produce 45*10=450 bottles per minute;

In 4 minutes 10 machines produce 450*4=1,800 bottles.

Answer: B.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 20 Aug 2012, 08:30
Ans=(270*10*4)/(6)
=1800

option B.
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 20 Aug 2012, 09:52
Each machine can produce (270/6) = 45 bottles per minute

45 * 10 = 450 bottles per minute

450 * 4 = 1800 bottles in 4 minutes.
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 24 Aug 2012, 02:22
SOLUTION

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

6 machines produce 270 bottles per minute;
1 machine produces 270/6=45 bottles per minute;
10 machines produce 45*10=450 bottles per minute;

In 4 minutes 10 machines produce 450*4=1,800 bottles.

Answer: B.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 12 Apr 2013, 10:11
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Let's take the approach that uses the answer choices to eliminate wasted time.

270/6 is a little less than 300/60 = 50 bottles per minute per machine. 10 machines = 500 per minute. 4 minutes worth = 2000 bottles as being slightly HIGHER than the answer we need.

Looking at the answers it is clear...we can only choose (B) 1800 bottles starting with an upper bound of 2000.
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Running at the same constant rate, 6 identical machines can prod [#permalink]

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New post 22 Apr 2013, 18:33
270/6 = 45 BPM X 10 Machines = 450 BPM X 4 MIN = 1,800.

Kudos if this is easier!
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 10 Sep 2014, 01:08
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600


6 identical machine produce 270bottles/min then 1machine - 45bottles/min

10 machine - 450 bottles/min

for 4 minutes--> 1800
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 15 Nov 2014, 21:52
better as fractions:

270*10/6*4/1=1800

B
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 20 Nov 2014, 01:59
Answer = B

Equation would be

\(= \frac{270}{6} * 10 * 4 = 1800\)
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 25 May 2016, 07:11
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800


To solve this problem, we first want to determine the rate of each machine. Since each machine works at the same constant rate, each machine’s rate is 270/6 = 45 bottles per minute. Now since there are 10 such machines, the rate of the 10 machines together is 10 x 45 = 450 bottles per minute.

Finally, we are asked to determine the number of bottles these 10 machines can produce in 4 minutes. Thus:

rate x time = work

450 x 4 = 1,800 bottles

Answer: B
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 25 May 2016, 08:55
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600


6 machines can produce 270 bottles, so 10 machines can produce 270*10/6

This can be produced in 1 minute. Total bottles that can be produced in 4 minutes :-
270*10*4/6= 1800 bottles

B is the answer
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Re: Running at the same constant rate, 6 identical machines can [#permalink]

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New post 05 Jul 2016, 05:04
Bunuel wrote:
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

Practice Questions
Question: 23
Page: 155
Difficulty: 600


r*t=w
we have 6 machine here so

6*(r*1)=270
r*1=45===> r=45

r*t=w

we got 10 machine
10*(r*t)=w
10*(45*4)=1800

t was 4 according to the question
B
Re: Running at the same constant rate, 6 identical machines can   [#permalink] 05 Jul 2016, 05:04
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