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Running at their respective constant rates, machine X takes [#permalink]
11 Mar 2007, 17:07
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Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
Lets assume Machine Y takes y days to produce w widgets.
Therefore Machine X takes (y+2) days to produce w widgets.
From above we can write:
Machine X produces w/(y+2) and Machine Y produces w/y widgets in 1 day.
So, if both Machines run together, both will produce w/(y+2) + w/y widgets.
In three days both machines will produce 3*(w/(y+2) + w/y) = 3w*(1/y + 1/(y+2)) widgets.
It's given that in 3 days both together also produce 5w/4
3w*(1/y + 1/(y+2)) = 5w/4
=> 1/y + 1/(y+2) = 5/12, by cancelling out w from both sides.
=> 5y^2 - 14y - 24 = 0
=> (y-4)*(5y+6) = 0
As y can not be -ve, so y = 4.
Now we can write
Machine X produces w widgets in (y+2)=6 days
so Machine X produces ww widgets in 2*6 = 12 days