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# S has 2,000 calories per kilogram, and 150 grams of protien

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Manager
Joined: 12 Feb 2007
Posts: 167
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Kudos [?]: 1 [0], given: 0

S has 2,000 calories per kilogram, and 150 grams of protien [#permalink]  21 Feb 2007, 13:26
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S has 2,000 calories per kilogram, and 150 grams of protien per kilogram.

T has 1,500 calories per kilogram, and 90 grams of protein per kilogram.

The table above gives the number of calories and grams of protein per kilogram of foods S and T. If a total of 7 kilograms of S and T are combined to make a certain food mixture, how many kilograms of food S are in the mixture?

(1) The mixture has a total of 12,000 calories.
(2) The mixture has a total of 810 grams of protein.

the answer says D, either is sufficient, however I say C. it seems you have 2 unknowns and 2 equations.

I know it cant be D because simply using (1), we know that you could have either 6 grams of S and 0 grams of T, or 8 grams of T and 0 grams of S. Both of these situations would add up to 12,000 calories, so therefore it cannot be D, right?
Intern
Joined: 11 Nov 2006
Posts: 31
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Kudos [?]: 0 [0], given: 0

(1) we need to come up with 12,000 cal. which means that there must be an even no. of T kilograms - 2, 4 or 6.

T kg. cal. S kg. cal. Total
2 3,000 5 10,000 13,000
4 6,000 3 6,000 12,000
6 9,000 1 2,000 11,000

Sufficient

(2) we need to come up with 810 g. of protein. Lets take T again and start from the middle.

T kg. g. protein S kg. g. protein Total
3 270 4 600 870
4 360 3 450 810

Sufficient

Manager
Joined: 29 Nov 2006
Posts: 83
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Kudos [?]: 3 [0], given: 0

the original question gives you one equation so all you need is just one more

D
VP
Joined: 22 Oct 2006
Posts: 1443
Schools: Chicago Booth '11
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Kudos [?]: 154 [0], given: 12

D as well, you have X + Y = 7 where x and y are the number of kilogrtams respectively

each statement gives you another statement , therefore each statement gives you 2 different equations 2 variables , which are both solvable
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