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S is a set containing 9 different numbers. T is a set contai [#permalink]
12 Aug 2008, 10:07

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Difficulty:

45% (medium)

Question Stats:

49% (01:54) correct
51% (00:57) wrong based on 63 sessions

S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of which are members of S. which of the following statements cannot be true?

A. The mean of S is equal to the mean of T B. The median of S is equal to the median of T C. The range of S is equal to the range of T D. The mean of S is greater than the mean of T E. The range of S is less than the range of T

Re: PS: Mean/Median [#permalink]
12 Aug 2008, 10:30

3

This post received KUDOS

E. Assuming a set cannot contain anything but integers.

vksunder wrote:

S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true? \

a) The mean of S is equal to the mean of T Take {1,2,3,4,5,6,7,8,9} for Set S => Mean is 5 so for Set t, remove number 5 and you have the same mean. Take {1,2,3,4,6,7,8,9} for set T b) The median of S is equal to the median of T Again, remove number 5 and you have 4 and 6, which you need the averge of the 4th and 5th numbers, (4 and 6 respectively) for the median of set T, again median is 5 too. c) The range of S is equal to the range of T Again, if you remove any of the numbers EXCEPT for 1 and 9 to get Set T, you still have 1 and 9 ans your ends so the range is 8 on both. d) The mean of S is greater than the mean of T mean of S with 1 through 9 is 5 (9 numbers with total of 45). If you remove number 9 to make Set T, you have 8 numbers with total of 36, or an average of less than 5 (average of 5 across 8 numbers would be a total of 40, so less than that would be less than 5 average) e) The range of S is less than the range of T 1 through 9 would be a range of 8. It would be impossible to have Set T to be within Set S and set S have a smaller range than set T because that would mean Set T included numbers not in set S.

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

Re: PS: Mean/Median [#permalink]
12 Aug 2008, 10:38

vksunder wrote:

S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true? \

a) The mean of S is equal to the mean of T possible : e.g S={3,5,4} T={3,5} b) The median of S is equal to the median of T possible S={2,4,6} T={2,6} c) The range of S is equal to the range of T POSSIBLE S={ 1,2,3,4} T ={1,2,4 } d) The mean of S is greater than the mean of T POSSIBLE e) The range of S is less than the range of T

Not possible E.

IF T is subset of S.. then Always range of S must be equal or greather than T

e.g S={ 1,2,3,4} range 3 T={1,2,3 } range 2 T ={1,2,4 } range 3 _________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: S is a set containing 9 different numbers. T is a set [#permalink]
17 Jan 2014, 09:35

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Re: S is a set containing 9 different numbers. T is a set contai [#permalink]
18 Jan 2014, 02:47

Expert's post

1

This post was BOOKMARKED

vksunder wrote:

S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of which are members of S. which of the following statements cannot be true?

A. The mean of S is equal to the mean of T B. The median of S is equal to the median of T C. The range of S is equal to the range of T D. The mean of S is greater than the mean of T E. The range of S is less than the range of T

The range of a set is the difference between the largest and smallest elements of a set.

Consider the set S to be {-4, -3, -2, -1, 0, 1, 2, 3, 4} --> mean=median=0 and range=8.

A. Mean of S = mean of T --> remove 0 from set S, then the mean of T still would be 0; B. Median of S = Median of T --> again remove 0 from set S, then the median of T still would be 0; C. Range of S = range of T --> again remove 0 from set S, then the range of T still would be 8; D. Mean of S > mean of T --> remove 4, then the mean of T would be negative -0.5 so less than 0; E. Range of S < range of T --> the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

Harvard asks you to write a post interview reflection (PIR) within 24 hours of your interview. Many have said that there is little you can do in this...