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Manager
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See the attached file [#permalink] New post 13 Jul 2006, 05:49
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A
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C
D
E

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Manager
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 [#permalink] New post 13 Jul 2006, 06:58
Area of equilateral triangle is Sqrt(4)* side * Side/4 = sqrt(3)*t^2/4

Area of square is s^2

Take ratio of t/4. This equals 2/sqrt(sqrt3) - Answer
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 [#permalink] New post 13 Jul 2006, 07:03
Area of Triangle = sqrt 3/4*t^2

Area of Square = s^2

Area of both the regions are same, so

sqrt 3/4*t^2 = s^2

t^2/s^2 = 4/sqrt 3

t/s = 2/3^1/4

Hence it is D
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 [#permalink] New post 13 Jul 2006, 07:21
(th)/2=s^2 – (1)

(t/2)^2+h^2=t^2
solving for h: --> h=((sqrt3)/2)t – (2)

substituting (2) in (1):

(sqrt3*t^2)/4=s^2
t^2/s^2=4/sqrt3
t/s=2/sqrt(sqrt3) – answer D
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 [#permalink] New post 13 Jul 2006, 22:35
Triangle is equilateral

Hence Area = Sqr(3)/4 * t^2

Area of square = s^2

Hence
Sqr(3)/4 * t^2 = s^2
t^2/s^2 = 4/sqr(3)

t/s = 2/(3)^1/4
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 [#permalink] New post 16 Jul 2006, 20:12
I am still confused...

I know the equation is

sqrt 3/4 (t^2)=s^2

Do I multiply the s^2 by 4 on the other side and get

3(t^2)=4s^2

I am confused from there..:(

Any assistance would be appreciated
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 [#permalink] New post 17 Jul 2006, 02:55
Zooroopa wrote:
jamesrwrightiii wrote:
I am still confused...

I know the equation is

sqrt 3/4 (t^2)=s^2

Do I multiply the s^2 by 4 on the other side and get

3(t^2)=4s^2


I am confused from there..:(

Any assistance would be appreciated


Nope √3 = 4(t^2s^2).

Now solve.



I thought the equation for are of equailateral triangle was

(square root 3/4)*s^2 ?
  [#permalink] 17 Jul 2006, 02:55
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