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# Seed mixture X is 40 percent ryegrass and 60 percent

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Intern
Joined: 27 Nov 2004
Posts: 30
Location: Vienna, Austria
Followers: 0

Kudos [?]: 2 [0], given: 0

Seed mixture X is 40 percent ryegrass and 60 percent [#permalink]  22 Jan 2005, 13:42
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0% (00:00) correct 0% (00:00) wrong based on 1 sessions
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?

(A) 10%
(B) 33,3%
(C) 40%
(D) 50%
(E) 66,67%

pls explain. thanks. f.
Director
Joined: 07 Jun 2004
Posts: 614
Location: PA
Followers: 3

Kudos [?]: 270 [0], given: 22

I am getting 33.33 % let me know if thats correct i will explain

thanks!
Intern
Joined: 27 Nov 2004
Posts: 30
Location: Vienna, Austria
Followers: 0

Kudos [?]: 2 [0], given: 0

ole ole...correct, rx!!

pls explain...

THANKS
Director
Joined: 07 Jun 2004
Posts: 614
Location: PA
Followers: 3

Kudos [?]: 270 [0], given: 22

the way i approcahed is in 2 steps

given .4x + .25y / x + y = 30% = .3

solve it u will get x=.5y from ------------ I

also we have to find percentage of x in the mixture

x / x + y from I

we get x / x + 2x = 1/3 = 33.33%
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# Seed mixture X is 40 percent ryegrass and 60 percent

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