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Sequence S consists of 24 nonzero integers. If each term in [#permalink]

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07 Aug 2010, 12:34

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Question Stats:

36% (02:28) correct
64% (01:30) wrong based on 629 sessions

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Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive (2) The fourth term in S is negative

The book claims this is one of the most diff questions GMAT can produce which I believe it is a joke....nevertheless got it wrong because I mis-interpreted the question. I am posting to see if more people will mis-interpret or if it is just me that is going *o*kers

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is negative (2) The fourth term in S is positive

The book claims this is one of the most diff questions GMAT can produce which I believe it is a joke....nevertheless got it wrong because I mis-interpreted the question. I am posting to see if more people will mis-interpret or if it is just me that is going *o*kers

Answer cannot be B, it should be A.

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is negative --> first and second terms must have opposite signs so we can hve following two scenarios:

-+--+--+--+-... OR: +--+--+--+--...

You can see that in both cases there is a repeated pattern of three terms in which 2 are negative and 1 positive (-+- or +--) so in both cases out of 24 terms 2/3 will be negative, so there will be 16 negative terms. Sufficient.

(2) The fourth term in S is positive --> either all terms are positive, so zero negatives or +--+... and not all terms are positive, so more than zero negatives. Not sufficient.

Answer: A.

If the OA is B then it should be:

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive --> either all terms are positive, so zero negatives or +--... and not all terms are positive, so more than zero negatives. Not sufficient.

(2) The fourth term in S is negative --> again two cases:

--+--+--+... OR -+--+--+-...

The same here: in both cases there is a repeated pattern of three terms in which 2 are negative and 1 positive (--+ or -+-) so in both cases out of 24 terms 2/3 will be negative, so there will be 16 negative terms. Sufficient.

the OA is def the one posted....double checked it..... will let more people get involved and then post the OA explanation.....your post supports my view that this question is not phrased correclt (ie is open to misinterpetation).....

the bigger question is how can we make sure that the practise we get is up to the test's standard if massive companies like Kaplan cannt phrase their questions correctly....

the OA is def the one posted....double checked it..... will let more people get involved and then post the OA explanation.....your post supports my view that this question is not phrased correclt (ie is open to misinterpetation).....

the bigger question is how can we make sure that the practise we get is up to the test's standard if massive companies like Kaplan cannt phrase their questions correctly....

Check the statements not the OA (placement of negative/positive in 1 and 2). There is nothing wrong with the question. _________________

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive (2) The fourth term in S is negative

The book claims this is one of the most diff questions GMAT can produce which I believe it is a joke....nevertheless got it wrong because I mis-interpreted the question. I am posting to see if more people will mis-interpret or if it is just me that is going *o*kers

One final question: I misinterpreted the If each term in S after the second part....thought that the "formula"/instructions (\(An= An-1 * An-2\) is only for the third onwards, thus we know nothing for the first two terms thus it is not possible to answer the question.....is that a valid conclusion....?

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive (2) The fourth term in S is negative

The book claims this is one of the most diff questions GMAT can produce which I believe it is a joke....nevertheless got it wrong because I mis-interpreted the question. I am posting to see if more people will mis-interpret or if it is just me that is going *o*kers

One final question: I misinterpreted the If each term in S after the second part....thought that the "formula"/instructions (\(An= An-1 * An-2\) is only for the third onwards, thus we know nothing for the first two terms thus it is not possible to answer the question.....is that a valid conclusion....?

You interpreted correctly: \(a_n=a_{n-1}*a_{n-2}\), for \(n>2\).

But you are not right about the first two terms for the following statements:

(2) The fourth term in S is negative --> \(a_4=negative=a_3*a_2\) --> second and third term must have opposite signs, so third term is either positive or negative. Now, case 1: if third term is positive then first and second terms must be both negative (for first and second it's not possible to be both positive as in this case fourth term would be positive too and we know that it's negative) and case 2: if third term is negative then first and second terms must have opposite signs. So there are only 2 cases possible:

--+--+--+... OR -+--+--+-...

In both cases there is a repeated pattern of three terms in which 2 are negative and 1 positive (--+ or -+-) so in both cases out of 24 terms 2/3 will be negative, so there will be 16 negative terms. Sufficient.

I also get B. You can establish a pattern at 4 and each combination to get negative (- * + or + * -) gets to the same number of negative numbers. I must admist that I did this the long way, without a formula - prorbably took a little over 2 minutes.

No clue! It's really tough one. Please give official explanation. A) and D) I have eliminated but I was confused between B) and C) because I was not able to explain stmt-B.

If you write out the options resulting from b

T3 below will be T1T2 T1 ---------- T2--------- T3--------------T4 -ve -ve +ve -ve -ve +ve -ve -ve

For both these cases expand out the first 8 terms and you will see the ratio of 2:1 for negative to positive!

Well after some thought; you may recognize the pattern that there are two negatives after every +ve; but I would rather write them all out and count them.

As you see for X; first position is -ve and the 2nd +ve. 3rd and 4th are negative and 5th +ve and the pattern continues. You may now count -ves. Likewise for Y.

Bunuel you are awesome ! If I had seen this question on test day I would have marked C and move on ! But then I took numbers and yes it answered. So - its imperative to find the first negative term. That is the key for the pattern ? Right?

Re: Sequence S consists of 24 nonzero integers. If each term in [#permalink]

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05 Jun 2013, 03:25

2

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Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive (2) The fourth term in S is negative

One important thing to understand is that in GMAT sequence questions there is almost always a pattern. So there is no real need to calculate all 24 integers' signs. The most difficult part in this question is: If each term in S after the second is the product of the previous two terms .

It is the same as saying that: x; y; xy; x(y^2); (x^2)(y^3); (x^3)(y^5); (x^5)(y^8); ...

1 st.) xy is positive. In this case both x and y are negative or they both positive. If both positive all the terms will be positive: (+) (+) (+) (+) (+) (+)... In case both are negative we have: (-) (-) (+) (-) (-) (-) (+).... Two different answers - statement is not sufficient

2 st.) x(y^2) is negative. There are two possible options: x is negative and y is positive, or x is negative and y is negative. In the 1st option we have the following pattern: (-) (+) (-) (-) (+) (-) (-) (+)... In the 2nd option we have the follwing pattern: (-) (-) (+) (-) (-) (+) (-) (-)... It starts slightly different but the pattern is the same, so we can conclude that the number of positives and negatives within 24 integers will be the same rerdless of the options. So the answer is B. _________________

If you found my post useful and/or interesting - you are welcome to give kudos!

Re: Sequence S consists of 24 nonzero integers. If each term in [#permalink]

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15 Apr 2014, 05:24

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive --> either all terms are positive, so zero negatives or +--... and not all terms are positive, so more than zero negatives. Not sufficient.

(2) The fourth term in S is negative --> again two cases:

--+--+--+... OR -+--+--+-...

The same here: in both cases there is a repeated pattern of three terms in which 2 are negative and 1 positive (--+ or -+-) so in both cases out of 24 terms 2/3 will be negative, so there will be 16 negative terms. Sufficient.

Re: Sequence S consists of 24 nonzero integers. If each term in [#permalink]

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10 May 2014, 12:11

1st term x 2nd term y S={x,y,xy,xy^2.........}

since 4th term is -ve , xY^2 is -ve i.e. x is -ve since y^2 cannot be -ve. Now since 1st term is -ve there can be 2 different pattern for the sequence assuming 2nd term to be either +ve or -ve.

S={-,-,+,-,-,+,......} or S={-,+,-,-,+,-,......}

So its clear that either 2nd term is +ve or -Ve the # of -ve terms is equal for 24 terms(since # of terms is a product of 3).

Re: Sequence S consists of 24 nonzero integers. If each term in [#permalink]

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07 Jul 2014, 09:30

ziko wrote:

Sequence S consists of 24 nonzero integers. If each term in S after the second is the product of the previous two terms, how many terms in S are negative?

(1) The third term in S is positive (2) The fourth term in S is negative

One important thing to understand is that in GMAT sequence questions there is almost always a pattern. So there is no real need to calculate all 24 integers' signs. The most difficult part in this question is: If each term in S after the second is the product of the previous two terms .

It is the same as saying that: x; y; xy; x(y^2); (x^2)(y^3); (x^3)(y^5); (x^5)(y^8); ...

1 st.) xy is positive. In this case both x and y are negative or they both positive. If both positive all the terms will be positive: (+) (+) (+) (+) (+) (+)... In case both are negative we have: (-) (-) (+) (-) (-) (-) (+).... Two different answers - statement is not sufficient

2 st.) x(y^2) is negative. There are two possible options: x is negative and y is positive, or x is negative and y is negative. In the 1st option we have the following pattern: (-) (+) (-) (-) (+) (-) (-) (+)... In the 2nd option we have the follwing pattern: (-) (-) (+) (-) (-) (+) (-) (-)... It starts slightly different but the pattern is the same, so we can conclude that the number of positives and negatives within 24 integers will be the same rerdless of the options. So the answer is B.

Why isn't fourth term x^2y^2

gmatclubot

Re: Sequence S consists of 24 nonzero integers. If each term in
[#permalink]
07 Jul 2014, 09:30

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