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Intern
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Series [#permalink] New post 07 Oct 2007, 08:10
How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.
Director
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Re: Series [#permalink] New post 07 Oct 2007, 08:26
hidalgo01 wrote:
How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.


not sure if this is the right logic:

4^(1/2) = 2
4^(1/3) = (2^2)^(1/3) = 2^2/3
4^(1/4) = (2^2)^(1/4) = 2^2/4 = sqrt 2

to simplify further:
2 + sqrt 2(2^1/6 + 1)

thats as far as i could go...
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 [#permalink] New post 08 Oct 2007, 14:11
question seems out of gmat league if the answer is compacter than beckee's
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Re: Series [#permalink] New post 08 Oct 2007, 19:04
hidalgo01 wrote:
How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.


We need options to arrive at a solution.
Re: Series   [#permalink] 08 Oct 2007, 19:04
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