Set A has 3 elements and set B has 4 elements. The number of : GMAT Problem Solving (PS)
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# Set A has 3 elements and set B has 4 elements. The number of

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Manager
Joined: 22 Sep 2010
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Set A has 3 elements and set B has 4 elements. The number of [#permalink]

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30 Sep 2010, 04:11
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45% (medium)

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22% (01:30) correct 78% (00:30) wrong based on 37 sessions

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Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A to B is

A. 144
B. 12
C. 24
D. 64
E. 124
[Reveal] Spoiler: OA
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Joined: 02 Sep 2009
Posts: 35951
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Kudos [?]: 90120 [0], given: 10418

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30 Sep 2010, 04:45
pzazz12 wrote:
Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A to B is

A. 144
B. 12
C. 24
D. 64
E. 124

But if interested as 3<4 then the number of injections from A to B is $$P^3_4=24$$. But again don't waste your time on this problem.
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Manager
Joined: 22 Sep 2010
Posts: 92
Followers: 2

Kudos [?]: 141 [0], given: 0

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01 Oct 2010, 04:03
Bunuel wrote:
pzazz12 wrote:
Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A to B is

A. 144
B. 12
C. 24
D. 64
E. 124

But if interested as 3<4 then the number of injections from A to B is $$P^3_4=24$$. But again don't waste your time on this problem.

thank you,but can you explain me little bit clear...........
Math Expert
Joined: 02 Sep 2009
Posts: 35951
Followers: 6866

Kudos [?]: 90120 [0], given: 10418

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01 Oct 2010, 04:36
pzazz12 wrote:
Bunuel wrote:
pzazz12 wrote:
Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A to B is

A. 144
B. 12
C. 24
D. 64
E. 124

But if interested as 3<4 then the number of injections from A to B is $$P^3_4=24$$. But again don't waste your time on this problem.

thank you,but can you explain me little bit clear...........

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Re: Functions........   [#permalink] 01 Oct 2010, 04:36
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