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Set A = [-x, -1, 1, 3, x], If the median is x/2, what is x?

are these in order by value? or is it just random? I don't see how it could be in order by value b/c that would mean x/2=1 and x=2, which wouldnt make any sense at all.

I get 0=x

b/c if we have -1,-x... then x must be less than 1 so---> -1,-x,x,1,3 thus x=x/2 --> 2x=x Only way this can be is if x=0.

i just assumed that set was already in increasing order. since there are an odd number of terms, the median is equal to 1, and if 1=x/2, that leads to x=2 .... am i oversimplifying this q ?

Set A = [-x, -1, 1, 3, x], If the median is x/2, what is x?

x >= 0 because there are at least 3 numbers that are greater or equal than 0 and x/2 is the median.

1) x - median -> x = x/2 -> x = 0 2) 1 - median -> x/2 = 1 -> x = 2

there are no other options because the median is greater or equal than zero and it can't be equal to 3 because there are at least 3 numbers smaller than 3.

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