i guess that the ans for the first one is B.

stat 1) -2,-1,0,1,2 and 2,3,4. here median are not same suppose from the first set, -2 and 2 were removed the median would be the same i.e if the other set was -1,0,1. insuff

stat2) the only way i can figure out that two sets having different no. of consecutive elemts have same sum, is if the median is zero. suff.

Good job!! eyunni
Great approach.
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Ya.. this approach is better than the algebraic approach which got me wrong. thanx.

'm' and 'r' are two numbers on the number line. What is the value of 'r'
1) The distance between r and 0 is three times the distance between m and 0
2) 12 is halfway between m and r.

I got this wrong but later figured out where i went wrong. Want to see if i can get a better and faster way to solve this one.

Thanks folks.[/quote]


I'm new here, but tackling this one I'm come up with both together are sufficient. I threw numbers in to solve the problem.

We know r = 3m

|-------m-------12--------3m
0

I plugged in a few numbers and found that if you plug in 6 for m, you get

|-----6------12------18
0

18 = 3 x 6, and 12 works as the midpoint. No other values will work here, so to me that answers the question. If I'm missing something- please let me know!

OAs

Q1 - c
Q2 - e

Thanx for all the suggestions folks..

Set S consists of 5 consecutive integers and set T consists of 7 consecutive integers. Is median of set S equal to the median of set T ?

1) Median of set S is 0
2) Sum of the numbers in S is equal to the sum of numbers in T

Haven't figured out the explanation for this yet..





is that the no. zero or the letter O ?
i considerd it as 0 and solved.
kindly clarify

For the second question : IMO E

1) The distance between r and 0 is three times the distance between m and 0 => r=3m or r=-3m.. not sufficient
2) 12 is halfway between m and r = > 12-m=r-12 = > not suffient as we have only one expression for 2 varaibles.

conbined..
if r=3m , from 12-m=r-12 => 24=4m=> m=6 and r=18
if r=-3m, from 12-m=r-12 => 2m=-24=> m -12 and r= 36
so, we are not sure.

Q1) given : S{5 consec integers},T{7 consecutive integers}
Question: MEDs=MEDt ?

1) Median of set S is 0 ->its INSUFFI since 7 cosecutive integers can be anywhere ,MEDt canbe 0 if all integers are about 0 (0 as median) or they can be scattered somewhere else on the number line with different median.

2) Sum of the numbers in S is equal to the sum of numbers in T
-> sum of 5 consecutive numbers = sum of 7 consec numbers

say S={n-2,n-1,n,n+1,n+2}
T={p-3,p-2,p-1,p,p+1,p+2,p+3}

5n=7p => if n=p=0 then only true for n and p o be integers .
hence SUFFI mean =0 for both and hence equal.

IMO B

Q2)given :'m' and 'r' are two numbers on the number line.
question :r=?
(1) The distance between r and 0 is three times the distance between m and 0 -> r and m can be on diffrent sides on the number line,r can be +ve or r can be -ve INSUFFICIENT ,again m can be any value (integer ,fraction etc).
2) 12 is halfway between m and r. =>again r ad m can be on same side of 0 or different side then different values of r.again m can be inteer ,fraction ,and r too can be .INSUFFI

(1) and (2) => is not SUFFI since both of them dont say about value of m whether integer or fraction and also no value of m ,hence for every value of m there can be a value for r even if 12 lies in between.INSUFFI

IMO E
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cheers
Its Now Or Never

my answer is B

(1) is ins

(2) is sufficient-

the only way the sum of the 2 sets is equal - for both sets, the mean and the average equal zero ==> symmetry around zero with an odd number of consequtive integers

example:

-2,-1,0,1,2

or -3,-2,-1,0,1,2,3

so (2) is sufficient