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# Set S consists of 5 consecutive integers. Set T consists of

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Senior Manager
Joined: 30 May 2005
Posts: 374
Followers: 1

Kudos [?]: 7 [0], given: 0

Set S consists of 5 consecutive integers. Set T consists of [#permalink]  18 Aug 2005, 08:07
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(N/A)

Question Stats:

100% (05:25) correct 0% (00:00) wrong based on 2 sessions
Set S consists of 5 consecutive integers. Set T consists of 7 consecutive integers. Is the median of S equal to the Median of T?

1) The median of S is 0

2) The Sum of the numbers in S is equal to the Sum of numbers in T
Manager
Joined: 15 Aug 2005
Posts: 199
Location: New York
Followers: 1

Kudos [?]: 1 [0], given: 0

I think the answer is C. Both conditions are needed.
Please correct me if I am wrong.

S= [-2,-1,0,1,2]

T= [-3,-2,-1,0,1,2,3]
Manager
Joined: 13 Oct 2004
Posts: 239
Followers: 1

Kudos [?]: 7 [0], given: 0

C.

St 1: Nothing about T, insufficient
St 2: if set S starts with x and set T with y, then:
5x+10 = 7y+21, this equation is satisified with x = -2, 5, 12 etc. This gives a yes and no answer, insufficient.

St1+st2 combined pegs x at -2 and the median of both sets at 0.
Manager
Joined: 28 Jun 2005
Posts: 217
Followers: 1

Kudos [?]: 2 [0], given: 0

St 1 not suff
st2 suff to answer the question

so B
Senior Manager
Joined: 29 Nov 2004
Posts: 486
Location: Chicago
Followers: 1

Kudos [?]: 9 [0], given: 0

Will go with B too..

IMO If sum of a set with 5 consec numbers and 7 consec numbers are same then the sum could only be 0, and the only possibility is a 0 in the middle flanked by positives and negatives...
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Fear Mediocrity, Respect Ignorance

Manager
Joined: 13 Oct 2004
Posts: 239
Followers: 1

Kudos [?]: 7 [0], given: 0

Ok, Here is a counter example for why B is not sufficient:

S = {5,6,7,8,9}
T = (2,3,4,5,6,7,8}

Another way to look at the second statement is that you have 2 variables -- the starting vlaues for S & T, and multiple value pairs satisfy this equation with equal and different medians.
Senior Manager
Joined: 04 May 2005
Posts: 284
Location: CA, USA
Followers: 1

Kudos [?]: 22 [0], given: 0

C

1) insuff
2) insuff
5 6 7 8 9 sum: 35 median: 7
2 3 4 5 6 7 8 sum: 35 median: 5

-9 -8 -7 -6 -5
-8 -7 -6 -5 -4 -3 -2

-2 -1 0 1 2 sum: 0 median: 0
-3 -2 -1 0 1 2 3 sum: 0 median: 0

1)+2) suff
Manager
Joined: 06 Aug 2005
Posts: 197
Followers: 3

Kudos [?]: 5 [0], given: 0

This was a good question.
If you do the algebra you get the answer right.
If you just guess at the obvious answer you got it wrong !
SVP
Joined: 03 Jan 2005
Posts: 2250
Followers: 13

Kudos [?]: 216 [0], given: 0

prep_gmat has the correct method of solving this kind of question.
_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Senior Manager
Joined: 29 Jun 2005
Posts: 403
Followers: 1

Kudos [?]: 15 [0], given: 0

Sorry for offtopic:
is 0 considered integer?
Manager
Joined: 06 Aug 2005
Posts: 197
Followers: 3

Kudos [?]: 5 [0], given: 0

Yes 0 is an integer.
0 is also a rational number and an even number.
It is not a positive number.

(It is sometimes regarded as a natural number too !)
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