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Set S consists of all prime integers less than 10. If two

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Set S consists of all prime integers less than 10. If two [#permalink] New post 29 Oct 2007, 22:49
Set S consists of all prime integers less than 10. If two numbers are chosen form set S at random, what is the probability that the product of these numbers will be greater than the product of the numbers which were not chosen?

1/3
2/3
1/2
7/10
4/5
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 [#permalink] New post 30 Oct 2007, 00:55
S = {2,3,5,7}
Winning sets (3,5) (3,7) (5,7)

# of ways to pick 2 numbers = 4C2 = 6

P = 3/6 = 1/2
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 [#permalink] New post 30 Oct 2007, 02:18
ywilfred wrote:
S = {2,3,5,7}
Winning sets (3,5) (3,7) (5,7)

# of ways to pick 2 numbers = 4C2 = 6

P = 3/6 = 1/2


Ywilfred - How did you calculate winning set - Winning sets (3,5) (3,7) (5,7) ?
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 [#permalink] New post 30 Oct 2007, 02:23
Since there are only four elements in the set, you can quickly calculate, say if we pick 2 and 3, the product would be 6, and the product of the remaining numbers would be 35 and so (2,3) cannot be a winning set since 6 < 35.
  [#permalink] 30 Oct 2007, 02:23
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Set S consists of all prime integers less than 10. If two

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